Legendary Polynomial & Bessel Functions MCQ Quiz - Objective Question with Answer for Legendary Polynomial & Bessel Functions - Download Free PDF
Last updated on May 19, 2025
Latest Legendary Polynomial & Bessel Functions MCQ Objective Questions
Legendary Polynomial & Bessel Functions Question 1:
is equal to
Answer (Detailed Solution Below)
Legendary Polynomial & Bessel Functions Question 1 Detailed Solution
Explanation:
From the identity of Bessel functions
Option (3) is true.
Legendary Polynomial & Bessel Functions Question 2:
P5(x) Q3(x) - Q5(x) P3(x) is equal to — (Where Pn(x) and Qn(x) are Legendre’s polynomials of first and second kind respectively)
Answer (Detailed Solution Below)
Legendary Polynomial & Bessel Functions Question 2 Detailed Solution
Explanation:
We know that
Pn(x) Qn-2(x) - Qn(x) Pn-2(x) =
Putting n = 5 we get
P5(x) Q3(x) - Q5(x) P3(x) =
Option (2) is true.
Legendary Polynomial & Bessel Functions Question 3:
If Pn(x) is Legendre polynomial, then P'n(1) is
Answer (Detailed Solution Below)
Legendary Polynomial & Bessel Functions Question 3 Detailed Solution
Explanation:
Putting x = 1 in the differential equation
(1 - x2)Pn''(x) - 2xPn'(x) + n(n + 1)Pn(x) = 0
we get
0 × Pn''(1) - 2Pn'(1) + n(n + 1)Pn(1) = 0
⇒ 2Pn'(1) = n(n + 1)Pn(1)
⇒ 2Pn'(1) = n(n + 1) (as Pn(1) = 1)
⇒ Pn'(1) =
Option (3) is true.
Legendary Polynomial & Bessel Functions Question 4:
The value of ∫ x2J1(x)dx will be
Answer (Detailed Solution Below)
Legendary Polynomial & Bessel Functions Question 4 Detailed Solution
Formula used:Recurrence Relations of Bessel’s Function:
This can be also written as
∫ xnJn-1(x)dx = xnJn(x)
Calculation:
We know that, from recurrence relations
∫ xnJn-1(x)dx = xnJn(x)
Put n = 2
∫ x2J1(x)dx = x2J2(x) + C
Additional Information
Bessel’s Equation:
The differential equation, recurrence relations
known as Bessel’s equation of order n and its particular solutions are called Bessel’s functions.
Top Legendary Polynomial & Bessel Functions MCQ Objective Questions
Legendary Polynomial & Bessel Functions Question 5:
The value of ∫ x2J1(x)dx will be
Answer (Detailed Solution Below)
Legendary Polynomial & Bessel Functions Question 5 Detailed Solution
Formula used:Recurrence Relations of Bessel’s Function:
This can be also written as
∫ xnJn-1(x)dx = xnJn(x)
Calculation:
We know that, from recurrence relations
∫ xnJn-1(x)dx = xnJn(x)
Put n = 2
∫ x2J1(x)dx = x2J2(x) + C
Additional Information
Bessel’s Equation:
The differential equation, recurrence relations
known as Bessel’s equation of order n and its particular solutions are called Bessel’s functions.
Legendary Polynomial & Bessel Functions Question 6:
is equal to
Answer (Detailed Solution Below)
Legendary Polynomial & Bessel Functions Question 6 Detailed Solution
Explanation:
From the identity of Bessel functions
Option (3) is true.
Legendary Polynomial & Bessel Functions Question 7:
P5(x) Q3(x) - Q5(x) P3(x) is equal to — (Where Pn(x) and Qn(x) are Legendre’s polynomials of first and second kind respectively)
Answer (Detailed Solution Below)
Legendary Polynomial & Bessel Functions Question 7 Detailed Solution
Explanation:
We know that
Pn(x) Qn-2(x) - Qn(x) Pn-2(x) =
Putting n = 5 we get
P5(x) Q3(x) - Q5(x) P3(x) =
Option (2) is true.
Legendary Polynomial & Bessel Functions Question 8:
If Pn(x) is Legendre polynomial, then P'n(1) is
Answer (Detailed Solution Below)
Legendary Polynomial & Bessel Functions Question 8 Detailed Solution
Explanation:
Putting x = 1 in the differential equation
(1 - x2)Pn''(x) - 2xPn'(x) + n(n + 1)Pn(x) = 0
we get
0 × Pn''(1) - 2Pn'(1) + n(n + 1)Pn(1) = 0
⇒ 2Pn'(1) = n(n + 1)Pn(1)
⇒ 2Pn'(1) = n(n + 1) (as Pn(1) = 1)
⇒ Pn'(1) =
Option (3) is true.
Legendary Polynomial & Bessel Functions Question 9:
The value of integral
Answer (Detailed Solution Below)
Legendary Polynomial & Bessel Functions Question 9 Detailed Solution
Concept Used:-
Beta function, or the Euler integral of first type, is a different type of function which is closely related to the gamma function and to binomial coefficients. The beta function for binomial coefficients m and n is given as,
Explanation:-
We have to find the value of integral
We know that,
On adding both the equations, we get
Now a beta function can be given as,
Put this value in equation (1),
So, the correct option is 2.