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A cylindrical specimen of length L and cross - sectional area A extends by δ under a gradually applied tensile load P. The strain energy of the specimen is

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BPSC AE Paper 4 (General Engineering Science) 10 Nov 2022 Official Paper
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  1. P δ 
  3. (stress on the cross - section) × (strain along the axis) × (volume of specimen)
  4. P δ 

Answer (Detailed Solution Below)

Option 1 : P δ 
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Detailed Solution

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Explanation:

The strain energy of a cylindrical specimen subjected to a gradually applied tensile load can be calculated using the formula for strain energy in elastic materials. Strain energy (UU U U) is the energy stored in a body due to deformation under loading.

For a cylindrical specimen of length L, cross-sectional area A, extension δ, and under a gradually applied tensile load P, the strain energy is given by:

U=1/2​×P×δ

Additional InformationThe elastic strain energy stored in a member of length (it may be curved or straight) due to axial force, bending moment, shear force and torsion are summarized below:

Axial Force, P

Bending, M

Shear Force, V

Torsion, T

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