A force F = 20 + 10y acts on a particle in y-direction where F is in newton and y in meter. Work done by this force to move the particle from y = 0 to y = 1 m is :

Question

Question

Answer 1

CONCEPT:

Work done by the force in the direction of the y-axis is written as;

Here, W is the work done, F is the force, y_f is the final position and y_i is the initial position.

CALCULATION:

By using work done by the variable force.It

-----(1)

Given: y_i = 0, yf = 1 m

and F = 20 + 10y

Now, On putting this value in equation (1) we have;

⇒

Hence, option 3) is the correct answer.