For pure bending, identify the WRONG statement.

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JKSSB JE CE 2021 Official Paper Shift 3 (Held on 29 Oct 2021)
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  1. Bending moment along the length of the member is zero
  2. The beam is subjected to pure moments or couple
  3. Shear force along the length of the member is zero
  4. The beam is bent into a circular arc of radius R

Answer (Detailed Solution Below)

Option 1 : Bending moment along the length of the member is zero
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Detailed Solution

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Explanation:

Pure bending along the entire beam ⇒ No shear force along the entire beam.

The deflected shape in case of pure bending is circular in shape

Pure bending in same part ⇒ No shear force in some part.

NOTE:

Statement 1 is false, as bending moment is not 0, in case of pure bending, as explained in the solution below.

Case I:

Simply supported beam subjected to equally space downward concentrated loads.

Case II:

SSB subjected to two equally spaced opposite moments.

Zero SF everywhere in beam. So, pure bending in entire length of beam.

Case III:

Cantilever beam subjected to the clockwise moment at the free end.

The bending moment at any cross-section will be equal to that of the moment applied at the free end.

Case IV:

Overhanging beam with both sides overhangs subjected to different concentrates loads at free ends.

∴ Case IV will be true only when P1 = P2.

∴ Case (I), (ii), and (iii) are pure bending cases.

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