उचित संख्या भरकर शृंखला की पूर्ती कीजिए। 

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Bihar STET Paper I: Hindi (9th Sept. 2020 - Shift 1)
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  1. 20
  2. 6
  3. 13
  4. 9

Answer (Detailed Solution Below)

Option 3 : 13
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Bihar STET Paper 1 Social Science Full Test 1
150 Qs. 150 Marks 150 Mins

Detailed Solution

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तर्क: दी गई आकृति में, ऊपर वाली संख्या, नीचे वाली संख्याओं के वर्ग का योगफल है।

पहली आकृति में,

 ⇒( 2)2 + (4)2 = 4 + 16 = 20

दूसरी आकृति में,

⇒ (3)2 + (9)2 = 9 + 81 = 90

इसी प्रकार, तीसरी आकृति में,

 ⇒ (2)2 + (3)2 = 4 + 9 = 13

अतः शृंखला में लुप्त पद "13" है।

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