Question
Download Solution PDFa ज्ञात कीजिए, यदि (1 + a)50 के विस्तार में 15वें और 16वें पद बराबर हैं।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंकल्पना:
(a + b)n के द्विपद विस्तार का सामान्य पद निम्न द्वारा दिया जाता है-
गणना:
हमारे पास है,
T15 = T14 + 1 = 50C14 (1)50 - 14 a14 = 50C14 a14
T16 = T15 + 1 = 50C15 (1)50 - 15 a15 = 50C15 a15
दिया जाता है कि
T15 = T16
⇒ 50C14 a14 = 50C15 a15
⇒ a = 15/36 = 5/12
अत: a =
Last updated on May 31, 2025
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