निम्नलिखित चार अक्षर-समूहों में से तीन एक निश्चित तरीके से एक जैसे हैं और एक अलग है। विषम का चयन कीजिए।

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Delhi Police Constable Previous Paper 6 (Held On: 27 Nov 2020 Shift 1)
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  1. KORVA 
  2. TXBFJ
  3. NRVZD
  4. PTXBF

Answer (Detailed Solution Below)

Option 1 : KORVA 
Free
Delhi Police Constable 2025 (Easy to Moderate) Full Test - 01
100 Qs. 100 Marks 90 Mins

Detailed Solution

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यहाँ अनुसरित स्वरूप निम्नलिखित हैं:

वर्णमाला अक्षर के स्थानों के अनुसार,

1) KORVA → K + 4 = O; O + 3 = R; R + 4 = V; V + 5 = A

2) TXBFJ → T + 4 = X; X + 4 = B; B + 4 = F; F + 4 = J

3) NRVZD → N + 4 = R; R + 4 = V; V + 4 = Z; Z + 4 = D

4) PTXBF → P + 4 = T; T + 4 = X; X + 4 = B; B + 4 = F

इसलिए, 'KORVA' विषम है।

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