Question
Download Solution PDFWater for a hydroelectric power station is obtained from a reservoir with a head of 150 m. What will be the approximate electrical power generated per hour per cubic meter of water if mechanical (hydro) efficiency is 0.85 and electric efficiency is 0.92?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept
The overall efficiency of a plant is:
Overall efficiency = Mechanical efficiency × Electrical efficiency
The electrical power generated per hour per cubic meter of water is given by:
P = W × H × η
where, P = Electrical power
W = Weight of water available/sec
H = Height
η = Overall efficiency
Calculation:
Given, Mechanical efficiency = 0.85
Electric efficiency = 0.92
η = 0.85 × 0.92
η = 0.782
H = 150 m
discharge, Q = 1 m3/sec
W = Q × Density of water × 9.81
W = 1 × 1000 × 9.81
W = 9810 N
P = 9810 × 150 × 0.782
P = 1150.7 kWh
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