What is the differential equation of ?

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NDA 02/2021: Maths Previous Year paper (Held On 14 Nov 2021)
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  1. xy2 + y1 = 0
  2. xy2 + 2y1 = 0
  3. xy2 - 2y1 = 0
  4. 2xy2 + y1 = 0

Answer (Detailed Solution Below)

Option 2 : xy2 + 2y1 = 0
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NDA 01/2025: English Subject Test
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Detailed Solution

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Formula used:

Calculation:

We have 

On differentiating the above equation with respect to x, we get 

 

⇒ x2 

again differentiate with respect to x

⇒ 

⇒ x

⇒ 

∴ The differential equation of  is .

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