A body of mass 'm' is moving uniformly along a circle having radius 'r'. The centripetal force on the body is:

  1. \(\dfrac{mv^2}{r}\)
  2. \(\dfrac{mv^2}{r^2}\)
  3. \(\dfrac{mv}{r^2}\)
  4. \(\dfrac{mv}{r}\)

Answer (Detailed Solution Below)

Option 1 : \(\dfrac{mv^2}{r}\)
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Explanation:

Centripetal Force: It is a force required to move a body uniformly in a circular motion. This force acts along the radius and towards the center of the circle.

  • When a body moves in a circle, its direction of motion at any instant is along the tangent of a circle. But according to Newton’s first law of motion, A body cannot change its direction of itself an external force is required for this purpose. This external force is the centripetal force

F1 J.S 6.6.20 Pallavi D1

\({\bf{Centripetal}}\;{\bf{Force}}\;\left( {\bf{F}} \right) = \frac{{m{v^2}}}{r}\;\left[ {{\rm{m}} = {\rm{mass}},{\rm{\;v}} = {\rm{velocity}},{\rm{\;r}} = {\rm{radius}}} \right]\)

F1 J.S 6.6.20 Pallavi D2

  • The centripetal force required for circular motion along the surface of the road, towards the center of the turn. The Static friction between tire and road provides the necessary centripetal force.
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