Question
Download Solution PDFA coil of 360 turns is linked by a flux of 200 μ Wb. If the flux is reversed in 0.01 second, then find the EMF induced in the coil.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Average induced emf is given by
Where N is the number of turns
dϕ is changing in flux
dt is changing in time
Calculation:
Given that, number of turns (N) = 360
Change in time (dt) = 0.01 s
Magnetic flux (ϕ) = 200 μWb
Since the flux is reversed, it changes from 200 μWb to -200 μWb, which is a change of 200 – (-200), i.e. 400 μWb
Change in magnetic flux (dϕ) = 400 μWb
Last updated on Jul 1, 2025
-> SSC JE Electrical 2025 Notification is released on June 30 for the post of Junior Engineer Electrical, Civil & Mechanical.
-> There are a total 1340 No of vacancies have been announced. Categtory wise vacancy distribution will be announced later.
-> Applicants can fill out the SSC JE application form 2025 for Electrical Engineering from June 30 to July 21.
-> SSC JE EE 2025 paper 1 exam will be conducted from October 27 to 31.
-> Candidates with a degree/diploma in engineering are eligible for this post.
-> The selection process includes Paper I and Paper II online exams, followed by document verification.
-> Prepare for the exam using SSC JE EE Previous Year Papers.