Two coils of 500 and 1000 turns are connected in series on the same magnetic circuit of reluctance 10⁶ AT/Wb. What will be the mutual inductance between them if there is no leakage?

Question

Question

This question was previously asked in

MPPGCL JE Electrical 28 April 2023 Shift 3 Official Paper

Answer 1

Concept

The mutual inductance between the coils is given by:

\(M={μ N_1N_2 A\over l}\)

\(M={ N_1N_2 \over l/\mu A}\)

\(M={ N_1N_2 \over S}\)

where, S = Reluctance

N = No. of turns

Calculation

Given, N1 = 500 and N2 = 1000

S = 106 AT/Wb

\(M={500\times 1000\over 10^6}\)

M = 0.5 H