A natural river is conveying a flow of 2500 cumec. What is the expected wetted perimeter of the river cross-section?

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BPSC AE Paper 6 (Civil) 25 March 2022 Official Paper
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  1. 23.75 m
  2. 2375 m
  3. 237.5 m
  4. 327.5 m

Answer (Detailed Solution Below)

Option 3 : 237.5 m
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Detailed Solution

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Explanation:

According to Lacey's theory, following formulae has been given below:

  1. Hydraulic mean depth, \(R = \frac{5}{2}\frac{{{V^2}}}{f}\)
  2. Area of the channel section, \(A = \frac{Q}{V}\)
  3. Wetted perimeter, \(P = 4.75\sqrt Q \)
  4. Regime mean velocity, \(V = {\left( {\frac{{Q{f^2}}}{{140}}} \right)^{1/6}}\)
  5. Bed Slope, \(S = \frac{{{f^{5/3}}}}{{3340{Q^{1/6}}}}\)

Calculation:

Q = 2500 cumec

\(P = 4.75\sqrt Q =4.75\sqrt {2500 }\) = 237.5 m

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