Question
Download Solution PDFA series resonant circuit has R = 2 Ω, L = 1 mH and C = 0.1 μF, the value of quality factor Q is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFCONCEPT:
The Quality factor: Quality factor of resonance is a dimensionless parameter that describes how underdamped an oscillator or resonator is.
Mathamaticaly, Q factor = \( \frac{1}{R} \sqrt{ \frac{L}{C}}\)
Where, L, C and R are the inductance, capacitance and resistance respectively.
EXPLANATION:
We know,
⇒ Q = \( \frac{1}{R} \sqrt{ \frac{L}{C}}\)
⇒ Q =\( \frac{1}{2} \sqrt{ \frac{1\times10^{-3}}{0.1\times10^{-6}}}\)
⇒Q=50
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