Question
Download Solution PDFDetermine the number of lamps required to illuminate a room of area 200 m2 to a level of 310 lx. Assume utilisation factor = 0.6, maintenance factor = 0.63 and the lumen output of each lamp = 2850 lm.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept
The number of lamps required to illuminate a room is given by:
\(N={E\times A\over F\times UF\times MF}\)
where, N = Number of lamps
E = Illuminance level (lux)
A = Area
F = Luminous flux per lamp (lm)
UF = Utilisation factor
MF = Maintenance factor
Calculation
Given, E = 300 lux
A = 200 m2
F = 2850 lm
UF = 0.6
MF = 0.63
\(N={310\times 200\over 2850\times 0.6\times 0.63}\)
N = 57.5 ≈ 58
Last updated on May 29, 2025
-> MPPGCL Junior Engineer result PDF has been released at the offiical website.
-> The MPPGCL Junior Engineer Exam Date has been announced.
-> The MPPGCL Junior Engineer Notification was released for 284 vacancies.
-> Candidates can apply online from 23rd December 2024 to 24th January 2025.
-> The selection process includes a Computer Based Test and Document Verification.
-> Candidates can check the MPPGCL JE Previous Year Papers which helps to understand the difficulty level of the exam.