Question
Download Solution PDFEvaluate: \(\rm \int_{0}^{\pi/2}\cos 2x\ dx\)
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Definite Integral:
If ∫ f(x) dx = g(x) + C, then \(\rm \int_a^b f(x)\ dx = [ g(x)]_a^b\) = g(b) - g(a).
Calculation:
Let I = \(\rm \int_{0}^{\pi/2}\cos 2x\ dx\)
⇒ I = \(\rm \left[\frac{\sin 2x}{2}\right]_0^{\pi/2}\)
⇒ I = \(\rm \left[\frac{\sin \pi}{2}-\frac{\sin 0}{2}\right]\)
⇒ I = 0.
Last updated on May 31, 2025
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