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Find out the value of x if logx 4 + logx 16 + logx 64 = 12

This question was previously asked in
Territorial Army Official Paper I (Conducted on 28 Jul 2019)
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  4. 54

Answer (Detailed Solution Below)

Option 2 : 2
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Detailed Solution

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Given:

logx 4 + logx 16 + logx 64 = 12

Formula Used:

If logx y = a, then xa = y

logx ab = b logx a

Calculation:

logx 4 + logx 16 + logx 64 = 12

⇒ logx 22 + logx 24 + logx 26 = 12

⇒ 2 logx 2 + 4 logx 2 + 6 logx 2 = 12

⇒ 12 logx 2 = 12

⇒ logx 2 = 1

⇒ 2 = x1

∴ x = 2

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