Question
Download Solution PDFFor a material with poisons ratio 0.25, the ratio of modulus of rigidity to modulus of elasticity will be
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
E = 2G(1 + v)
where E = Modulus of elasticity, G = Modulus of rigidity, ν = Poisons ratio.
Calculation:
Given:
Poisson's ratio, v = 0.25
the ratio of modulus of rigidity to modulus of elasticity = \(\frac{G}{E}\)
\(\frac{G}{E} = \frac{1}{{2\left( {1 + v} \right)}}\)
\(\frac{G}{E} = \frac{1}{{2\left( {1 + 0.25} \right)}}\)
\(\frac{G}{E} = 0.4\)
Hence the required value of the ratio of modulus of rigidity to modulus of elasticity is 0.4.
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