Question
Download Solution PDFGeeta runs 5/2 times as fast as Babita. In a race, if Geeta gives a lead of 40 m to Babita, find the distance from the starting point where both of them will meet (correct up to two decimal places).
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
Geeta runs 5/2 times as fast as Babita
Geeta gives a lead of 40 m to Babita
Formula Used:
Distance = Speed × Time
Calculation:
Let the speed of Babita be 2x
⇒ Speed of Geeta = (5/2) × 2x = 5x
Let the distance covered by Geeta be y meters
⇒ Distance covered by Babita = (y - 40) meters
As time is constant, distance is directly proportional to speed
⇒
⇒ 2y = 5y - 200
⇒ y = 200/3 = 66.67m
∴ The distance from the starting point where both of them will meet is 66.67 m
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