Question
Download Solution PDFउचित संख्या भरकर शृंखला की पूर्ती कीजिए।
This question was previously asked in
Bihar STET Paper I: Hindi (9th Sept. 2020 - Shift 1)
Answer (Detailed Solution Below)
Option 3 : 13
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Bihar STET Paper 1 Social Science Full Test 1
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Detailed Solution
Download Solution PDFतर्क: दी गई आकृति में, ऊपर वाली संख्या, नीचे वाली संख्याओं के वर्ग का योगफल है।
पहली आकृति में,
⇒( 2)2 + (4)2 = 4 + 16 = 20
दूसरी आकृति में,
⇒ (3)2 + (9)2 = 9 + 81 = 90
इसी प्रकार, तीसरी आकृति में,
⇒ (2)2 + (3)2 = 4 + 9 = 13
अतः शृंखला में लुप्त पद "13" है।
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