Question
Download Solution PDFवह संख्या ज्ञात कीजिए जिसे क्रमागत रूप से 5, 7 और 9 से विभाजित करने पर क्रमशः 2, 0 और 2 शेषफल बचते हैं, और अंतिम भागफल 15 है।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है:
भाजक: 5, 7, 9
शेषफल: 2, 0, 2
अंतिम भागफल: 15
प्रयुक्त सूत्र:
भाज्य = (भाजक × भागफल) + शेषफल
गणनाएँ:
तीसरा भाग: 9 × 15 + 2 = 137
दूसरा भाग: 7 × 137 + 0 = 959
पहला भाग: 5 × 959 + 2 = 4797
इसलिए, वह संख्या 4797 है।
Last updated on May 29, 2025
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