Question
Download Solution PDFसमतल 5x + 2y + z - 13 = 0 द्वारा बनाए गए निर्देशांक अक्षों पर अन्तःखंडों की लंबाइयाँ क्या हैं?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFधारणा:
- समतल का अन्तःखंड रूप निम्न द्वारा दिया जाता है ⇔ \(\frac{x}{a} + \frac{y}{b} + \frac{z}{c} = 1\)
जहाँ ‘a’ x- अन्तःखंड है, 'b' y- अन्तःखंड है और 'c' z- अन्तःखंड है।
गणना:
दिया हुआ:
समतल का समीकरण 5x + 2y + z – 13 = 0
⇒ 5x + 2y + z = 13
\(\Rightarrow \frac{{5{\rm{x\;}} + {\rm{\;}}2{\rm{y\;}} + {\rm{\;z\;}}}}{{13}} = 1\)
\(\Rightarrow \frac{x}{{\frac{{13}}{5}}} + \frac{y}{{\frac{{13}}{2}}} + \frac{z}{{\frac{{13}}{1}}} = 1\)
∴ अन्तःखंडों की लंबाइयाँ \(\frac{{13}}{5},\frac{{13}}{2},\;13\) इकाई हैंLast updated on May 30, 2025
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