Question
Download Solution PDFश्रृंखला 3, 6, 9, 12, 15, .......के पहले 18 पदों का योग क्या है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंकल्पना:
1 से n तक क्रमागत संख्याओं का योग:
\(\rm1 + 2 + 3 +\ ...\ + n = \dfrac{n(n+1)}{2}\).
गणना:
दी गयी श्रृंखला में पहले 18 पदों के योग को निम्न रूप में लिखा जा सकता है:
3 + 6 + 9 + 12 + 15, .......
⇒ 3(1 + 2 + 3 + 4 + 5 + ....)
⇒ \(\frac{3 \times 18 \times 19}{2} = 513\)
Last updated on May 31, 2025
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