If I_CEO = 410 μA, I_CBO = 5 μA and I_B = 30 μA, then the collector current is:

Concept: +

ICEO is the reverse leakage current in the common-emitter configuration of BJT when the base is open.

ICBO is the reverse leakage current in the common-base configuration of BJT when the emitter is open.

Also, ICEO > ICBO

And they are related by the relation:

ICEO = (1 + β) ICBO

Total collector current is given by:

IC = βIB + ICBO(β + 1)

Application:

Given:

ICEO = 410 μA, ICBO = 5 μA and IB = 30 μA

ICEO = (1 + β) ICBO

410 = (β + 1)5

β = 81

Now,

IC = βIB + ICBO(β + 1)

= (81 x 30 + 410)μA

= 2.84 mA