In Mendelian dihybrid cross, how many types of genotypes and phenotypes will be present?

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UP TGT Biology 2011 Official Paper
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  1. 4 and 9 respectively.
  2. 9 and 4 respectively.
  3. 9 and 16 respectively.
  4. 4 and 12 respectively.

Answer (Detailed Solution Below)

Option 2 : 9 and 4 respectively.
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Concept-

  • Gregor Mendel conducted hybridization experiments on garden peas for seven years (1856-1863).
  • A dihybrid cross describes a mating experiment between two organisms that are identically hybrid for two traits.
  • A hybrid organism is one that is heterozygous, which means that carries two different alleles at a particular genetic position.
  • Therefore, a dihybrid organism is one that is heterozygous at two different genetic loci.
  • Gregor Mendel performed dihybrid crosses on pea plants and discovered a fundamental law of genetics called the Law of Independent Assortment.

Explanation-

  • Mendel selected traits for dihybrid cross for his experiments-
    • Colour of cotyledons- Yellow (Y) and Green (y).
    • Seed shape - Round (R) and Wrinkled (r).

F1 Hemant Agarwal Anil 12.03.21 D4

  • The phenotypic ratio produced is 9: 3: 3: 1.
  • The genotypic ratio produced is 1: 2: 2: 4: 1: 2: 1: 2: 1.

Therefore the 9 types of genotype and 4 types of the phenotype are present in the mendelian dihybrid cross.

Additional Information

  • Monohybrid Cross
    • Phenotypic ratio- 3: 1
    • Genotypic ratio- 1: 2: 1
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