In the figure given below, O is the centre of the circle. If ∠APQ = 35°, find the value of ∠OQP.

  1. 35°
  2. 45°
  3. 55°
  4. 65°

Answer (Detailed Solution Below)

Option 3 : 55°
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RRB NTPC CBT-I Official Paper (Held On: 4 Jan 2021 Shift 1)
100 Qs. 100 Marks 90 Mins

Detailed Solution

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According to the alternate segment theorem, the angle between a tangent and a chord at the point of contact is equal to the angle made by the chord in the alternate segment of the circle

In the figure given,

⇒ ∠APQ = ∠QRP = 35°

As we know, the angle subtended by an arc at the centre of the circle is twice the angle subtended by the arc at any other point on the circle

⇒ ∠QOP = 2 × ∠QRP = 2 × 35° = 70°

Now, considering ΔOQP,

∵ OQ = OP = radius of circle

⇒ ΔOQP is an isosceles triangle

⇒ ∠OQP = ∠OPQ

∵ Sum of angles of triangle = 180°

⇒ ∠QOP + ∠OQP + ∠OPQ = 180°

∴ ∠OQP = (180° – 70°)/2 = 110°/2 = 55°

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