Question
Download Solution PDFदिलेल्या आकृतीमध्ये, ∠ABC = 81° आणि ∠ACB = 9°. ∠BDC चे मूल्य किती आहे?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिलेल्याप्रमाणे:
∠ABC = 81°
∠ACB = 9°
वापरलेली संकल्पना:
परिघावरील कोन रेषेवर समान चापाद्वारे समान आहेत.
त्रिकोणाच्या अंतर्गत कोनांची बेरीज 180° आहे.
गणना:
△ ABC मध्ये
⇒ ∠ABC +∠ACB + ∠BAC = 180° (कोनाची बेरीज गुणधर्म)
⇒ 81° + 9° + ∠BAC = 180°
⇒ ∠BAC = 180° - 90° = 90°
आता,
⇒ ∠BAC = ∠BDC = 90° (समान विभागातील कोन)
∴ योग्य उत्तर ∠BDC = 90 ° आहे.
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