Question
Download Solution PDFDE is a chord and KDE is a secant of a circle. If KD = 9 cm, DE = 7 cm and KH is a tangent to the circle at point H, then find KH.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
DE is the chord of a circle.
KD = 9 cm ; DE = 7 cm
Concept used:
If a tangent and a secant are drawn from a common point outside the circle then,
Tengent2 = line of secant × (line of sacant - chord)
Calculation:
From tangent and secant relation:
⇒ KH2 = KD × KE
⇒ KH2 = 9 × 16
⇒ KH = √144 = 12 cm
∴ The correct answer is 12 cm.
Last updated on Jun 2, 2025
-> The SSC Exam Dates 2025 has been released on the official website.
-> The SSC CGL Notification 2025 will be released on 9th June 2025 at ssc.gov.in.
-> The SSC CGL application 2025 submission will be open from 9th June to 4th July 2025.
-> The SSC CGL Tier 1 Exam 2025 Dates have been revised. The SSC CGL Exam will be conducted from 13 August to 30 August, 2025.
-> Candidates can refer to the SSC CGL syllabus for a better understanding of the exam structure and pattern.
-> The SSC CGL Eligibility is a bachelor’s degree in any discipline.
-> Candidates selected through the SSC CGL exam will receive an attractive salary. Learn more about the SSC CGL Salary Structure.
-> Attempt SSC CGL Free English Mock Test and SSC CGL Current Affairs Mock Test.
-> Candidates should also use the SSC CGL previous year papers for a good revision.