Question
Download Solution PDF12 सेमी त्रिज्येच्या वर्तुळाच्या क्षेत्राचे क्षेत्रफळ 32 π सेमी2 आहे क्षेत्राच्या संबंधित कंसाची लांबी शोधा.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिलेले आहे:
वर्तुळाच्या क्षेत्राचे क्षेत्रफळ = 32 π सेमी2
वर्तुळाची त्रिज्या (R) = 12 सेमी
वापरलेले सूत्र:
क्षेत्राचे क्षेत्रफळ = (π × R2 × θ)/360
कंसाची लांबी = (2 × π × R × θ)/360
गणना:
क्षेत्राचे क्षेत्रफळ = (π × R2 × θ)/360
⇒ 32π = (π × (12)2 × θ)/360
⇒ 32 × 360 = (144 × θ)
⇒ θ = (32 × 360)/144
⇒ θ = 80°
कंसाची लांबी = (2 × π × R × θ)/360
⇒ (2 × π × 12 × 80)/360
⇒ (16/3) × π
∴ योग्य उत्तर
Last updated on Jun 25, 2025
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