Question
Download Solution PDF12 సెం.మీ వ్యాసార్ధం గల వృత్తఖండం యొక్క వైశాల్యం 32 π సెం.మీ2 వృతఖండము యొక్క సంబంధిత చాపం యొక్క పొడవును కనుగొనండి.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFఇచ్చిన:
వృత్తఖండం వైశాల్యం = 32 π సెం.మీ2
వృత్తం యొక్క వ్యాసార్థం (R) = 12 సెం.మీ
ఉపయోగించిన ఫార్ములా:
వృత్తఖండం యొక్క వైశాల్యం= (π × R 2 × θ)/360
చాపం పొడవు = (2 × π × R × θ)/360
లెక్కింపు:
వృత్తఖండం యొక్క వైశాల్యం = (π × R 2 × θ)/360
⇒ 32π = (π × (12)2 × θ)/360
⇒ 32 × 360 = (144 × θ)
⇒ θ = (32 × 360)/144
⇒ θ = 80°
చాపం పొడవు = (2 × π × R × θ)/360
⇒ (2 × π × 12 × 80 )/360
⇒ (16/3) × π
∴ సరైన సమాధానం
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