Question
Download Solution PDFThe average gate power dissipation for an SCR is 0.5 W. Gate voltage variation is 2 V to 10 V. Which of the following is true?
Answer (Detailed Solution Below)
Vg = 2 V, Ig = 0.25 A;
Vg = 10 V, Ig = 0.05 A
Detailed Solution
Download Solution PDFSolution:
Given,
Average gate power dissipation = 0.5 W
i.e., Pg = Vg Ig = 0.5 W
Given Range of Gate voltage is 2 V to 10 V
Case (i)
Consider, Vg = 2 V
∴ \(\rm I_g = \frac{P_g}{V_g} = \frac{0.5}{2}= 0.25 \ A\)
Case (ii)
Consider, Vg = 10 V
\(\therefore \rm I_g = \frac{0.5}{2}= 0.05 \ A\)
Therefore, the correct option will be 1.
Last updated on Mar 26, 2025
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