Question
Download Solution PDFThe current in the 4Ω resistor in the figure shown below is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFThe correct answer is option 4):(
Concept:
Calculation:
Assuming voltage (V) at node A :
Applying KVL at node A, we have
⇒ V= -20/3 V
The current flowing through the 4 Ω resistance from A to B =
=
Last updated on Jun 16, 2025
-> SSC JE Electrical 2025 Notification will be released on June 30 for the post of Junior Engineer Electrical/ Electrical & Mechanical.
-> Applicants can fill out the SSC JE application form 2025 for Electrical Engineering from June 30 to July 21.
-> SSC JE EE 2025 paper 1 exam will be conducted from October 27 to 31.
-> Candidates with a degree/diploma in engineering are eligible for this post.
-> The selection process includes Paper I and Paper II online exams, followed by document verification.
-> Prepare for the exam using SSC JE EE Previous Year Papers.