Question
Download Solution PDFThe current in the 4Ω resistor in the figure shown below is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFThe correct answer is option 4):(\(5 \over 3\) A and flowing from B to A)
Concept:
Calculation:
Assuming voltage (V) at node A :
Applying KVL at node A, we have
\({V-20\over 2}+{V\over 4}+15=0\)
⇒ V= -20/3 V
The current flowing through the 4 Ω resistance from A to B = \(-\frac{20}{3\times 4} = -\frac{5}{3}\) A
= \(5\over 3\)A and flowing from B to A
Last updated on Jun 16, 2025
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