Question
Download Solution PDFThe decomposition of NH3 on platinum surface is zero order reaction. If k = 2.5 × 10-4 mol L-1s-1 the rate of production of H2 is
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDF\(2 \mathrm{NH}_3 \stackrel{\mathrm{Pt}}{\longrightarrow} \mathrm{N}_2+3 \mathrm{H}_2\)
As reaction is zero order
Rate = k[NH3]0
Rate = k
Rate = \(\frac{-1}{2} \frac{\Delta\left[\mathrm{NH}_3\right]}{\Delta \mathrm{t}}=\frac{1}{3} \frac{\Delta\left[\mathrm{H}_2\right]}{\Delta \mathrm{t}}=\mathrm{k}\)
\(\frac{\Delta H}{\Delta t}=3 k\)
= 3 × 2.5 × 10–4
= 7.5 × 10–4 mol L–1 s–1
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