The distance between the plates of a parallel plate capacitor is tripled keeping other parameters unchanged. The new capacitance will become-

  1. Three times of the initial capacitance
  2. One third of the initial capacitance
  3. Nine times of the initial capacitance
  4. Remains unchanged

Answer (Detailed Solution Below)

Option 2 : One third of the initial capacitance
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CONCEPT:

  • The capacitance of a capacitor (C): The capacitance of a conductor is the ratio of charge (Q) to it by a rise in its potential (V), i.e.

C = Q/V

  • The unit of capacitance is the farad, (symbol F ).

Parallel Plate Capacitor:

F1 P.Y Madhu 13.04.20 D9

  • parallel plate capacitor consists of two large plane parallel conducting plates of area A and separated by a small distance d.

 Mathematical expression for the capacitance of the parallel plate capacitor is given by:

\(C = \frac{{{\epsilon_o}A}}{d}\)

Where C = capacitance, A = area of the two plates, εo = permittivity of free space, and d = separation between the plates,

EXPLANATION:

Since \(C = \frac{{{\epsilon_o}A}}{d}\)

  • From the above equation, it is clear that the capacitance of the capacitor is inversely proportional to the distance between the plates of the parallel plate capacitor.
  • Hence, if the distance between the plates of a parallel plate capacitor is tripled then the capacitance of the capacitor will become one-third of the initial capacitance.
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