Receivers MCQ Quiz in বাংলা - Objective Question with Answer for Receivers - বিনামূল্যে ডাউনলোড করুন [PDF]

Last updated on Mar 9, 2025

পাওয়া Receivers उत्तरे आणि तपशीलवार उपायांसह एकाधिक निवड प्रश्न (MCQ क्विझ). এই বিনামূল্যে ডাউনলোড করুন Receivers MCQ কুইজ পিডিএফ এবং আপনার আসন্ন পরীক্ষার জন্য প্রস্তুত করুন যেমন ব্যাঙ্কিং, এসএসসি, রেলওয়ে, ইউপিএসসি, রাজ্য পিএসসি।

Latest Receivers MCQ Objective Questions

Top Receivers MCQ Objective Questions

Receivers Question 1:

In a standard AM superheterodyne receiver, if the IF is 455 kHz and the high-side tuning is used, the local oscillator frequency must vary between.

  1. 885 kHz – 1585 kHz
  2. 85 kHz – 1145 kHz
  3. 1005 kHz – 2105 kHz
  4. 88 kHz – 108 kHz

Answer (Detailed Solution Below)

Option 3 : 1005 kHz – 2105 kHz

Receivers Question 1 Detailed Solution

Concept:

In a standard AM superheterodyne receiver the local oscillator frequency (\({f_{Lo}}\)) is given by:

For high side tunning or up-conversion, we have:

\({f_{Lo}} = {f_s} + {f_{IF}}\)

For low side tunning or down-conversion, we have:

\({f_{Lo}} = {f_s} - {f_{IF}}\)

Where,

fS: carrier frequency of the desired AM radio signal.

fIf : intermediate frequency.

Calculation:

Given: fIf = 455 kHz

The carrier frequency allocation range for AM signal is 550kHz – 1650kHz

Hence,

\(({f_{Lo}})min = 550 + 455 = 1005~kHz\)

And,

\(({f_{Lo}})max = 1650 + 455 = 2105~kHz\)

∴ The local oscillator frequency varies from 1005 kHz - 2105 kHz

Receivers Question 2:

A communication receiver has an intermediate frequency of 9 MHz. What is the frequency of its oscillator when it is tuned to 15 MHz?

  1. 24 MHz
  2. 12 MHz
  3. 9 MHz
  4. 15 MHz

Answer (Detailed Solution Below)

Option 1 : 24 MHz

Receivers Question 2 Detailed Solution

Concept:

For super heterodyne receiver:

fi = fl - fs

Where,

fl = Local oscillator frequency

fi = Intermediate frequency

fs = Desired signal frequency

Calculation:

Given,

fi = 9 MHz

fs = 15 MHz

fi = fl - fs

fl = fi + fs

= (9 + 15) MHz

= 24 MHz

Receivers Question 3:

Arrange the following components sequentially from the output to input in a superheterodyne receiver.

i. Antenna

ii. IF amplifier

iii. Mixer

iv. Audio amplifier

  1. i, ii, iii and iv 
  2. iv, iii, ii and i 
  3. i, iii, iv and ii 
  4. iv, ii, iii, and i

Answer (Detailed Solution Below)

Option 4 : iv, ii, iii, and i

Receivers Question 3 Detailed Solution

The Block Diagram of a Superheterodyne Receiver is represented as:

Indian bank PO FT 4 11 Q (1) REV.docx 17

Arranging the components sequentially from the output to input, we have:

Audio Amplifier, IF Amplifier, Mixer, Antenna (At the very left used to receive the electromagnetic wave)

RF amplifier is tuned to select and amplify a particular carrier frequency within the AM broadcast range.

Only the selected frequency and its two sidebands are allowed to pass through the amplifier.

Detailed Block Diagram:

F1 S.B Deepak 19.02.2020 D1

  • A superheterodyne receiver changes the RF frequency to a lower IF frequency. This IF frequency will be amplified and demodulated to get a video signal.
  • Generally, Mixer will do the down Conversion in Superheterodyne Receiver i.e.

           IF = fL – fs 

Receivers Question 4:

In a broadcast superheterodyne receiver, having no RF amplifier, the IF = 455 kHz. What is the image frequency if the receiver is tuned to 1000 kHz?

  1. 1455 kHz
  2. 1910 kHz
  3. 545 kHz
  4. 2455 kHz

Answer (Detailed Solution Below)

Option 2 : 1910 kHz

Receivers Question 4 Detailed Solution

Concept:

Image frequency: The signal which causes interference is called ‘image frequency’

Image frequency and intermediate frequency is related as follows:

fsi = fs + 2 IF

fs: carrier frequency of the tuned station

fsi: image frequency

IF: Intermediate frequency

Calculation:

Given intermediate frequency (I.F) = 455 kHz

Tuned signal frequency is fs = 1000 kHz

Image frequency is

fsi = 1000 kHz + 2 × 455 kHz

fsi = 1910 kHz

Receivers Question 5:

The preamplifier used in a Hi-Fi system has:

  1. low noise high gain
  2. low noise medium gain
  3. high noise low gain
  4. medium noise medium gain

Answer (Detailed Solution Below)

Option 1 : low noise high gain

Receivers Question 5 Detailed Solution

  • The primary function of a preamplifier is to extract the signal from the detector without significantly degrading the intrinsic signal-to-noise ratio.
  • The preamplifier used in Hi-Fi system has low noise and high gain and is located as close as possible to the detector, and the input circuits are designed to match the characteristics of the detector.
  • A preamp used for high-fidelity audio supports two audio channels (stereo) and switches between audio inputs such as an FM tuner, CD player and digital media player.

Receivers Question 6:

In an AM system receiver. the mixer translates the carrier frequency fc to a fixed intermediate frequency of 450 kHz. Given a broadcast signal of frequency 900 kHz. What is the corresponding image frequency when a superhetrodyne receiver is employed with local oscillator frequency greater than the broadcast signal frequency?

  1. 900 kHz
  2. 1800 kHz
  3. 800 kHz
  4. 1350 kHz

Answer (Detailed Solution Below)

Option 2 : 1800 kHz

Receivers Question 6 Detailed Solution

Concept:

Image Frequency

  • It is an undesired input frequency at the receiver end which can also be demodulated by the superheterodyne receivers along with the desired incoming signal. This results in two stations being received at the same time, resulting in interference.
  • Image frequency is given by fi = fRF + 2fIF­, where fRF = frequency of desired incoming signal and

           fIF = Intermediate frequency.

           Graphically,

           F2 S.B Madhu 11.10.19 D 12

Calculation:

fi = fRF + 2fIF­

fi = 900 + 2(450) = 1800 kHz

Receivers Question 7:

The IF is 455 kHz. If the radio receiver is tuned to 855 kHz, the local oscillator frequency is ______.

  1. 455 kHz
  2. 1310 kHz
  3. 1500 kHz
  4. None of these

Answer (Detailed Solution Below)

Option 2 : 1310 kHz

Receivers Question 7 Detailed Solution

Concept:

The image frequency for a super-heterodyne receiver is given by:

fsi = fs + 2IIF

fsi = Image frequency

fs = Tuned frequency of the signal

IIF = Intermediate frequency

fLO = Local Oscillator frequency, which is calculated as:

fLO = fs + IF

This is explained with the help of the following spectrum analysis:

Assignment 8 Soumya UPPCL AE EC 2016 10  5

Calculation:

With fIF = 455 kHz and  fs = 855 kHz, the oscillator frequency will be:

fLO = fs + IF = 855 kHz + 455 kHz

fLO = 1310 kHz

Receivers Question 8:

Which among the following is TRUE with respect to de-emphasis?

1. De-emphasis is a complement of pre-emphasis.

2. It decreases the magnitude of higher frequencies with respect to the magnitude of other lower frequencies.

3. It is used in FM broadcasting.

4. It improves the SNR.

  1. 1 and 2
  2. 1, 2 and 3
  3. 1, 2 and 4
  4. 2, 3 and 4

Answer (Detailed Solution Below)

Option 3 : 1, 2 and 4

Receivers Question 8 Detailed Solution

De-emphasis:

  • The de-emphasis circuit is used at the receiver side of FM modulation to return the original frequency response.
  • De-emphasis circuit de-amplifies the higher frequency components as it is, i.e. it decreases the magnitude of higher frequencies with respect to the magnitude of other lower frequencies.
  • De-emphasis is a complement of pre-emphasis, i.e. pre-emphasis circuit only amplifies the high-frequency component without changing the low-frequency amplitude.
  • By doing this, it provides an extra noise immunity to the FM signal and SNR of FM signal gets improved.

 

F1 S.B 31.7.20 Pallavi D2

Pre-Emphasis:

  • Since in FM, higher frequency components of message signal are more prone to noise as compared to low-frequency components because of which the signal to noise ratio of the FM signal gets degrades at a higher frequency.
  • ∴  To improve the SNR of FM signal, we add a circuitry before frequency modulator and this circuit is known as the Pre-emphasis circuit.
  • The pre-emphasis circuit only amplifies the high-frequency component without changing the low-frequency amplitude and by doing this it provides an extra noise immunity to the FM signal and SNR of the FM signal gets improved.

 

F1 S.B 31.7.20 Pallavi D1

Receivers Question 9:

In a radio receiver, which of the following stages does not need alignment ___________

  1. TRF stage
  2. IF stage
  3. antenna input stage
  4. audio stage

Answer (Detailed Solution Below)

Option 4 : audio stage

Receivers Question 9 Detailed Solution

Alignment is a process where several stages of the receiver are properly tuned to the desired frequency.

The input to the audio stage is a demodulated message signal and does not require any alignment to receive the desired frequency.

In electronics, a super-heterodyne receiver uses frequency mixing to convert a received signal to a fixed intermediate frequency (IF) which can be more conveniently processed than the original carrier frequency and audio stage does not need alignment in a radio receiver.

Receivers Question 10:

The most popular intermediate frequency (in kHz) for receivers tuning from 540 kHz to 1650 kHz is __________.

  1. 422
  2. 433
  3. 444
  4. 555

Answer (Detailed Solution Below)

Option 4 : 555

Receivers Question 10 Detailed Solution

Image Frequency: 

It is an undesired input frequency at the receiver end which can also be demodulated by the superheterodyne receivers along with the desired incoming signal. This results in two stations being received at the same time, resulting in interference.

The Image frequency is given by:

fi = fRF + 2fIF­

fRF = frequency of desired incoming signal

fIF = Intermediate frequency.

Graphically:

           F2 S.B Madhu 11.10.19 D 12

Calculation:

To avoid the problem of Image Frequency,

540 kHz + 2(IF) ≥ 1650 kHz

2IF ≥ 1110 MHz  

IF ≥ 555 kHz

(IF)min = 555 kHz

Get Free Access Now
Hot Links: teen patti plus teen patti master gold teen patti game - 3patti poker