Clock and Calendar MCQ Quiz - Objective Question with Answer for Clock and Calendar - Download Free PDF

According to the given question, we need to find the day of the 14th of the given month.

Statement 1: The last day of the month is a Wednesday.

If the last day is Wednesday we are not able to find a day on the 14th of that month because we don't know whether the month is of 28 days or 29 days or 30 days or 31 days.

Therefore, Statement-1 alone is not sufficient to answer the question.

Statement 2: The third Saturday of the month was seventeenth.

If the 17th day of the given month is Saturday then we can easily find the 14th day by subtracting 3 odd days from Saturday i.e., (6 - 3) = 3. means Wednesday.

Therefore, Statement-2 alone is sufficient to answer the question.

Hence, "Option 2" is the correct answer.

Additional InformationHere we use odd days as: Sunday = 0 , Monday = 1, Tuesday = 2, Wednesday = 3, Thursday = 4, Friday = 5, and Saturday = 6.  

Given:  Determine the overlapping work hours:

8:00 AM - 2:00 PM: Group 1 is present.

10:00 AM - 4:00 PM: Group 2 is present.

12:00 PM - 6:00 PM: Group 3 is present.

Analyze the overlapping periods:

8:00 AM - 10:00 AM: 5 people (Group 1)

10:00 AM - 12:00 PM: 15 people (Group 1 and Group 2)

12:00 PM - 2:00 PM: 20 people (Group 1, Group 2, and Group 3)

2:00 PM - 4:00 PM: 15 people (Group 2 and Group 3)

4:00 PM - 6:00 PM: 5 people (Group 3)

The period with the most people present is between 12:00 PM and 2:00 PM, with 20 people

Therefore, the computer is most likely to be used most commonly during the hours of 12 PM to 2 PM.

Hence, the correct answer is "Option 1".

From 14th September to 17th October:

Days left in September:

September has 30 days, so days remaining after the 14th = 30 - 14 = 16 days.

Days in October before the 17th:

Days = 17 days.

Total days between the two dates:

Total = 16 (September) + 17 (October) = 33 days.

Calculate the day of the week:

33 days modulo 7 gives us the remainder when divided by 7:

33 ÷ 7 = 5

32 ÷ 7 = 4 remainders 5

Starting from Tuesday (14th September):

Counting 5 days from Tuesday:

Tuesday → Wednesday (1) → Thursday (2) → Friday (3) → Saturday (4) →Sunday(5)

Thus, 17th October will be a Sunday.

Hence the correct answer is, Option(3)

To determine if a particular year is a leap year, we can follow these rules:

1. A year is a leap year if it is divisible by 4.
2. However, if the year is divisible by 100, it is not a leap year, unless:
3. The year is also divisible by 400, in which case it is a leap year.

Now, let's check each option,

1) 1600: It is a leap year because it is divisible by 400.

2) 2000: It is a leap year because it is divisible by 400.

3) 2400: It is a leap year because it is divisible by 400.

Hence, the correct answer is "All options are correct".

Given: a 12-hour clock when the time is 9 ∶ 25.

Formula used:

\(\text{Angle between the minute hand and the hour hand}={(60 \:H - 11\:M)\over 2}\)

where H represents hour and M represents minutes.

Calculation:

\(\text{Angle between the minute hand and the hour hand}={(60 \times9\: - \:11\times25)\over 2}\)

\(\text{Angle between the minute hand and the hour hand}={265\over 2} = 132.5^\circ\)

Thus, the approximate angle between the minute hand and the hour hand is ' \(\textbf{130}^\circ\: \)'.

The logic followed here is:

3 march 2020 was Tuesday

First of all we will check is 2020 is a leap year 2020/4

so, 2020 is a leap year therefore February has 29 days.

Now, we will check days between 4 Feb 2020 - 3 march 2020

i.e. 26 + 3 odd days

   = 29/7( because week has 7 days )

remainder is 1 by dividing it

so we will -1 in Tuesday i.e. Monday

therefore 3 Feb 2020 is Monday

but, we have to find 3 Feb 2019

then we will do -1 in Monday

so, on 3 February 2019 is Sunday

Hence, Sunday is the correct answer.

Statements:

I. Harish was born on an even date of the month → 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28

II. Harish’s birth date was a prime number → 2, 3, 5, 7, 11, 13, 17, 19, 23, 29

But we know that 2 is the smallest even prime number.

According to both statements we can say that on 2nd February 2000 Harish was born.

Hence, Option (1) is correct.

Logic: If we see carefully we can find that these dates have property  \({ {yy^2}} = { {dd^2}} + { {mm^2}} \)

3rd April, 2005 - 03/04/05  

\({ {(05)^2}} = { {(03)^2}} + { {(04)^2}} \)

6th August, 2010 - 06/08/10

\({ {(10)^2}} = { {(06)^2}} + { {(08)^2}} \)

5th December, 2013 - 05/12/13

\({ {(13)^2}} = { {(05)^2}} + { {(12)^2}} \)

Similarly,

Independence day 2017 - 15 August 2017 - 15/08/17

By above logic: \({ {(17)^2}} = { {(15)^2}} + { {(08)^2}} \) 

No other option satisfy the above condition. So, Indian Independence Day of 2017 has the same property.

Hence, option 1) is the correct answer.

Formula Used:

Θ = | Hours × 30^◦ - \( {11 \ \over2}\) × Minute |

Calculation:

Θ = | 2 × 30◦ - \( {11 \ \over2}\) × 13 |

Θ = | 60◦ - \( {143 \ \over2}\)|

Θ = | 60◦ - 71.5◦ |

Θ = | - 11.5◦ |

Θ = 11.5◦ 

Hence, "11.5◦"  will be the acute angle between the hour-hand and the minute-hand at 2:13 p.m

Calculation:   

The angle between two digits = 30° 

⇒ At 2'o clock one hand will be on 12 and second hand will be on 2 So, 30° × 2 = 60° 

∴ At 2'o clock angles between hands will be 60°.

Given - 

January 1, 2018 was Monday

Concept used - 

in a normal year number of days = 365

number of odd days = (365/7) = + 1

Solution - 

1 January 2018 = Monday

1 January 2019 = Monday + 1 = Tuesday

∴ January 1, 2019 = Tuesday  

Statement I: February 15 of this year was a Wednesday: We cannot get what is today’s date.

Statement II: Today is March 12: We can’t tell which day today is, it can be any day.

Taking both the statements together: We cannot tell whether it is Friday or not because we don’t know if the year is leap year or not.

The logic followed here is:

1600 years contain 0 odd day, 300 years contain 1 odd day. Also, 83 years contain 20 leap years and 63 ordinary years and therefore (40+0) odd days i.e., 5 odd days.

∴ 1983 years contain (0 + 1 + 5) i.e., 6 odd days.

Number of days from Jan. 1984 to 15th Oct. 1984

= (31 + 29 + 31 + 30 + 31 + 30 +31+ 31 + 30 + 15)

= 289 days = 2 odd days

∴ Total number of odd days = 6 + 2 = 1 odd days.

So, 15th Oct, 1984 was Monday.

Hence, the correct answer is "Monday".

Given:

⇒ January 20, 2030 = Sunday

⇒ January 22, 2030 = Tuesday

As, for each month dates 1, 8, 15, 22 and 29 comes on same week day.

⇒ January 1, 2030 = Tuesday

⇒ January 4, 2030 = Friday

⇒ January 4, 2029 = Thursday

As after every leap year, dates will move two days further and 2028 is a leap year. Leap year is a year which is divisible by 4 and having 366 days.

∴ January 4, 2028 = Tuesday

Given: a 12-hour clock when the time is 9 ∶ 25.

Formula used:

\(\text{Angle between the minute hand and the hour hand}={(60 \:H - 11\:M)\over 2}\)

where H represents hour and M represents minutes.

Calculation:

\(\text{Angle between the minute hand and the hour hand}={(60 \times9\: - \:11\times25)\over 2}\)

\(\text{Angle between the minute hand and the hour hand}={265\over 2} = 132.5^\circ\)

Thus, the approximate angle between the minute hand and the hour hand is ' \(\textbf{130}^\circ\: \)'.