Data MCQ Quiz - Objective Question with Answer for Data - Download Free PDF

Given:

Bonus (in lakh Rs) from 1998 to 2002: 3.00, 2.52, 3.84, 3.68, 3.96

Salary (in lakh Rs) from 1998 to 2002: 288, 342, 324, 336, 420

Formula used:

Percentage = \(\frac{\text{Total Bonus}}{\text{Total Salary}} × 100\)

Calculation:

Total Bonus = 3.00 + 2.52 + 3.84 + 3.68 + 3.96 = 16.99 lakh

Total Salary = 288 + 342 + 324 + 336 + 420 = 1710 lakh

Percentage = \(\frac{16.99}{1710} × 100\)

⇒ \(0.993\%\) ≈ 1%

∴ The correct answer is approximately 1%

Given:

Formula used:

Total Expenditure = Salary + Fuel and Transport + Bonus + Interest on Loans + Taxes

Calculations:

Total Expenditure in 2001 = 336 + 133 + 3.68 + 36.4 + 88

Total Expenditure in 2001 = 597.08

∴ The total expenditure of the company over these items during the year 2001 is 597.08.

Given:

Height of the child on the 7th birthday = 125 cm

Height of the child on the 10th birthday = 150 cm

Formula used:

Percentage increase = ((New value - Old value) / Old value) × 100

Calculation:

Percentage increase in height from the 7th birthday to the 10th birthday:

⇒ Percentage increase = ((150 - 125) / 125) × 100

⇒ Percentage increase = (25 / 125) × 100

⇒ Percentage increase = 0.2 × 100 = 20%

The percentage increase in the height of the child from the 7th birthday to the 10th birthday is 20%.

Given:

The production data for four products (P, Q, R, S) by four cities (A, B, C, D) is provided.

Formula used:

Total production of a product = Sum of production across all cities

Calculation:

Total production of P = 1500 + 1200 + 1100 + 1450 = 5250

Total production of Q = 1250 + 1400 + 1250 + 1500 = 5400

Total production of R = 1600 + 1150 + 1150 + 1300 = 5200

Total production of S = 1750 + 1050 + 1000 + 1250 = 5050

∴ The product with the highest total production is Q with 5400 units.

Given:

The production (in units) and sales, of different items of a steel company.

Formula used:

Unsold items = Production - Sales

Calculation:

For Plate: Unsold items = 252 - 190 = 62

For Bowl: Unsold items = 356 - 307 = 49

For Spoon: Unsold items = 185 - 133 = 52

For Pipe: Unsold items = 220 - 155 = 65

For Holder: Unsold items = 458 - 419 = 39

Hence,

Holder is the item which has least number of unsold items.

Calculation

We  have 20% of 50 = 10

Therefore Required number:

Number of students scoring less than 10 marks in aggregate

= 100 - Number of students scoring 10 and above marks in aggregate

= 100 - 87

= 13.

The number of students scoring less than 20% marks in aggregate is 13.

Calculation:

Total marks = 50

Eligible for higher studies in mathematics marks = 50 × 60% = 30

Total students who are eligible to pursue higher studies in mathematics = 33 

∴ The correct answer is 33.

Calculation:

State T has witnessed two times increase in 2016 and 2017 or 2020 and 2021.

State A has witnessed two times increase in 2019 and 2020

State M has witnessed two times increase in 2019 and 2020

State K has witnessed two times increase in 2020 and 2021

So, total 4 states witnessed an increase in the amount of annual rainfall continuously for two times in immediate years

∴ The required answer is 4.

Calculation:

Total selected from Delhi = 94 + 48 + 90 + 70 + 82 = 384

Total selected from Maharastra = 85 + 70 + 84 + 60 + 65 = 364

Required percentage = (364 × 100)/384 = 94.79%

∴ The correct answer is 94.79%.

Calculation:

Number of delivery partners that joined Pyntra in 2017 = 5.6

Number of delivery partners that joined Pyntra in 2021 = 7.2

Increase in the number of delivery partners that joined Pyntra = 7.2 - 5.6

⇒ 1.6

% increase = (1.6/5.6) × 100

⇒ 28.57%

∴ The required answer is 28.57%.

Calculation:

Now, the average wage of the employees

⇒ (85 × 9 + 95 × 3 + 105 × 31 + 115 × 5 + 125 × 2)/(9 + 3 + 31 + 5 + 2) = 513/5 

⇒ 102.6

⇒ 100 < 102.6 < 110

∴ The average wage of the employees lies between 100-110.

Calculation:

Total students placed in different companies in the year 2014 = 19300 +13400 +13400 + 11800 + 7800 = 65700

Total students placed in different companies in the year 2012 = 12600 + 9800 +10400 + 14900 + 9800 = 57500

Required difference = 65700 - 57500 = 8200 students

∴ The correct answer is 8200.

Calculation:

Total income of C1 in year P = 750

Total income of C2 in year Q = 250

So, required % = (750/250) × 100

⇒ 300%

So, statement I is wrong

Total income of C1 and C2 in T year = 530 + 270

⇒ 800

Average income = 800/2 = 400

So, statement II is correct

∴ The required answer is Option 1.
Mistake Point

We have to find which statement is not correct.

The income of C1 in year P is 300% of the income of C2 in year Q. So statement 1 is not correct.

The average income of C1 and C2 in year T is 400. So statement 2 is correct.

That's why option 1 is the correct answer. Please go through the question again.

Calculation:

Number of accountant after 2015 = 35

Number of accountant after 2016 = 35 + 26 - 16

⇒ 45

Number of accountant after 2017 = 45 + 15 - 5

⇒ 55

Number of accountant after 2018 = 55 + 20 - 38

⇒ 37

Number of accountant after 2019 = 37 + 14 - 24

⇒ 27

∴ The required answer is 27.

Calculation:

Number of students from C who passed in science but failed in Mathematics = 8

Total number of students in C = 18 + 10 + 8 + 56

⇒ 92

Required % = (8/92) × 100

⇒ 8.695 ≈ 8.7%

∴ The required answer is 8.70%.