De Morgan Laws of Propositional Logic MCQ Quiz - Objective Question with Answer for De Morgan Laws of Propositional Logic - Download Free PDF
Last updated on Mar 11, 2025
Latest De Morgan Laws of Propositional Logic MCQ Objective Questions
Top De Morgan Laws of Propositional Logic MCQ Objective Questions
De Morgan Laws of Propositional Logic Question 1:
Match the following.
|
List-1 |
List -2 |
|
(I) (X’)’ |
(A) De Morgan law |
|
(II) (X + Y)’=X’.Y’ |
(B) Involution |
|
(III) X(X+Y) = X |
(C) Distributive |
|
(IV) X + YZ = (X +Y) (X+Z) |
(D) Absorption |
Answer (Detailed Solution Below)
Option 2 : I – B, II – A, III –D, IV - C
India's Super Teachers for all govt. exams Under One Roof
De Morgan Laws of Propositional Logic Question 1 Detailed Solution
(X’)’ = X → involution law.
X + Y)’=X’.Y’ → De Morgan Law
X(X+Y) = X + XY = X → Absorption law
X + YZ = (X +Y) (X+Z) → Distributive law
India’s #1 Learning Platform
Start Complete Exam Preparation
Daily Live MasterClasses
Practice Question Bank
Mock Tests & Quizzes
Trusted by 7.2 Crore+ Students
De Morgan Laws of Propositional Logic Question 2:
Which of the following is equivalent to \(\sim ∃(P(x)∧Q(y))\)?
Answer (Detailed Solution Below)
Option 3 : \(∀x(P(x)→\sim Q(y))\)
De Morgan Laws of Propositional Logic Question 2 Detailed Solution
The correct answer is option 3 i.e. \(∀x(P(x)→\sim Q(y))\)
Proof: \(\sim ∃(P(x)∧Q(y))\)
\(∀x\sim (P(x)∧Q(y))\)
\(∀x(\sim P(x)∨\sim Q(y))\)
\(∀x(P(x)→\sim Q(y))\)
India’s #1 Learning Platform
Start Complete Exam Preparation
Daily Live MasterClasses
Practice Question Bank
Mock Tests & Quizzes
Trusted by 7.2 Crore+ Students