Quantitative Aptitude MCQ Quiz - Objective Question with Answer for Quantitative Aptitude - Download Free PDF
Last updated on Jun 6, 2025
Latest Quantitative Aptitude MCQ Objective Questions
Quantitative Aptitude Question 1:
The price of a commodity increased by 22%. By what percentage (correct to two decimal places) should its consumption be reduced so that the total expenditure remains the same?
Answer (Detailed Solution Below)
Quantitative Aptitude Question 1 Detailed Solution
Given:
The price of a commodity increased by 22%.
Formula used:
Let the original consumption be 100 units.
New price = 100 + 22 = 122
Total expenditure should remain the same.
Calculations:
Original expenditure = 100 × 100
New expenditure = 122 × (new consumption)
⇒ 10000 = 122 × (new consumption)
⇒ new consumption = 10000/122
⇒ new consumption ≈ 81.97 units
Reduction in consumption = 100 - 81.97
⇒ Reduction in consumption ≈ 18.03 units
Percentage reduction = (18.03/100) × 100
⇒ Percentage reduction ≈ 18.03%
∴ The correct answer is option (4).
Quantitative Aptitude Question 2:
The annual salary of Aprajita is 150% of Sonia’s annual salary. Sonia’s salary rises by 20% after an increment, whereas Aprajita’s salary increases by 12%. If the initial salary of Sonia was Rs. 6,00,000, then what is the salary of Aprajita (in Rs.) now after a hike?
Answer (Detailed Solution Below)
Quantitative Aptitude Question 2 Detailed Solution
Given:
Sonia's initial salary = ₹6,00,000
Aprajita's initial salary = 150% of Sonia's salary
Sonia's salary increment = 20%
Aprajita's salary increment = 12%
Formula used:
New Salary = Initial Salary × (1 + Increment Rate)
Calculation:
Aprajita's initial salary = 1.5 × ₹6,00,000
⇒ Aprajita's initial salary = ₹9,00,000
New Salary of Aprajita = ₹9,00,000 × (1 + 0.12)
⇒ New Salary of Aprajita = ₹9,00,000 × 1.12
⇒ New Salary of Aprajita = ₹10,08,000
∴ The correct answer is option 1.
Quantitative Aptitude Question 3:
A bag contains 4800 g of rice. 20% of rice is added in the bag after which 10% quantity is taken out. Then 15% quantity is added back in the bag. Lastly, 25% of rice is taken out of the bag. What is the weight of the bag now, in grams?
Answer (Detailed Solution Below)
Quantitative Aptitude Question 3 Detailed Solution
Given:
Weight of the rice in the bag = 4800 g
Formula Used:
New Weight = Original Weight + Added Weight - Removed Weight
Calculation:
20% of 4800 g is added:
Added Weight = 4800 × 20 / 100 = 960 g
New Weight = 4800 + 960 = 5760 g
10% of 5760 g is taken out:
Removed Weight = 5760 × 10 / 100 = 576 g
New Weight = 5760 - 576 = 5184 g
15% of 5184 g is added back:
Added Weight = 5184 × 15 / 100 = 777.6 g
New Weight = 5184 + 777.6 = 5961.6 g
25% of 5961.6 g is taken out:
Removed Weight = 5961.6 × 25 / 100 = 1490.4 g
New Weight = 5961.6 - 1490.4 = 4471.2 g
The weight of the bag now is 4471.2 grams.
Quantitative Aptitude Question 4:
In an election between two candidates, 64% of the voters cast their votes, out of which 4% of the votes were declared invalid. A candidate got 12,288 votes which were 64% of the total valid votes. Find the total number of votes enrolled in that election.
Answer (Detailed Solution Below)
Quantitative Aptitude Question 4 Detailed Solution
Given:
In an election between two candidates, 64% of the voters cast their votes, out of which 4% of the votes were declared invalid. A candidate got 12,288 votes which were 64% of the total valid votes.
Formula used:
Total votes enrolled = Total valid votes / (Percentage of valid votes cast × Percentage of voters who cast their votes)
Calculation:
Total valid votes = 12,288 / 0.64
⇒ Total valid votes = 19,200
Total votes cast = Total valid votes / 0.96
⇒ Total votes cast = 19,200 / 0.96
⇒ Total votes cast = 20,000
Total votes enrolled = Total votes cast / 0.64
⇒ Total votes enrolled = 20,000 / 0.64
⇒ Total votes enrolled = 31,250
∴ The correct answer is option (1).
Quantitative Aptitude Question 5:
The numbers of boys and girls in a college are in the ratio of 5 ∶ 3. If 24% of the boys and 32% of the girls were not placed in campus placements, then the percentage of students who got jobs in campus placements is:
Answer (Detailed Solution Below)
Quantitative Aptitude Question 5 Detailed Solution
Given:
The ratio of boys and girls in a college is 5 : 3
24% of boys and 32% of girls are not placed in campus placements.
Calculation:
Let the total number of students be 800.
The number of boys = 800 × 5/8 = 500
The number of girls = 800 × 3/8 = 300
According to the question,
24% of boys and 32% of girls are not placed in campus placements.
The percentage of boys who got jobs in campus placements = 100% - 24% = 76%
⇒ 76% of 500 = 380
The percentage of girls who got jobs in campus placements = 100% - 32% = 68%
⇒ 68% of 300 = 204
Total placements = 380 + 204 = 584
∴ Percentage of placements = (584/800) × 100 = 73%
∴ The percentage of those students who got jobs in campus placements is 73%.
Top Quantitative Aptitude MCQ Objective Questions
If x −
Answer (Detailed Solution Below)
Quantitative Aptitude Question 6 Detailed Solution
Download Solution PDFGiven:
x - 1/x = 3
Concept used:
a3 - b3 = (a - b)3 + 3ab(a - b)
Calculation:
x3 - 1/x3 = (x - 1/x)3 + 3 × x × 1/x × (x - 1/x)
⇒ (x - 1/x)3 + 3(x - 1/x)
⇒ (3)3 + 3 × (3)
⇒ 27 + 9 = 36
∴ The value of x3 - 1/x3 is 36.
Alternate Method If x - 1/x = a, then x3 - 1/x3 = a3 + 3a
Here a = 3
x - 1/x3 = 33 + 3 × 3
= 27 + 9
= 36
A shopkeeper earns a profit of 25 percent on selling a radio at 15 percent discount on the Printed price. Finds the ratio of the Printed price and the cost price of the radio.
Answer (Detailed Solution Below)
Quantitative Aptitude Question 7 Detailed Solution
Download Solution PDFGiven:
Profit = 25 Percent
Discount = 15 Percent
Formula:
MP/CP = (100 + Profit %)/(100 – Discount %)
MP = Printed Price
CP = Cost Price
Calculation:
We know that –
MP/CP = (100 + Profit %)/(100 – Discount %) ………. (1)
Put all given values in equation (1) then we gets
MP/CP = (100 + 25)/(100 – 15)
⇒ 125/85
⇒ 25/17
∴ The Ratio of the Printed price and cost price of radio will be 25 ∶ 17Six chords of equal lengths are drawn inside a semicircle of diameter 14√2 cm. Find the area of the shaded region?
Answer (Detailed Solution Below)
Quantitative Aptitude Question 8 Detailed Solution
Download Solution PDFGiven:
Diameter of semicircle = 14√2 cm
Radius = 14√2/2 = 7√2 cm
Total no. of chords = 6
Concept:
Since the chords are equal in length, they will subtend equal angles at the centre. Calculate the area of one sector and subtract the area of the isosceles triangle formed by a chord and radius, then multiply the result by 6 to get the desired result.
Formula used:
Area of sector = (θ/360°) × πr2
Area of triangle = 1/2 × a × b × Sin θ
Calculation:
The angle subtended by each chord = 180°/no. of chord
⇒ 180°/6
⇒ 30°
Area of sector AOB = (30°/360°) × (22/7) × 7√2 × 7√2
⇒ (1/12) × 22 × 7 × 2
⇒ (77/3) cm2
Area of triangle AOB = 1/2 × a × b × Sin θ
⇒ 1/2 × 7√2 × 7√2 × Sin 30°
⇒ 1/2 × 7√2 × 7√2 × 1/2
⇒ 49/2 cm2
∴ Area of shaded region = 6 × (Area of sector AOB - Area of triangle AOB)
⇒ 6 × [(77/3) – (49/2)]
⇒ 6 × [(154 – 147)/6]
⇒ 7 cm2
∴ Area of shaded region is 7 cm2
There is a rectangular garden of 220 metres × 70 metres. A path of width 4 metres is built around the garden. What is the area of the path?
Answer (Detailed Solution Below)
Quantitative Aptitude Question 9 Detailed Solution
Download Solution PDFFormula used
Area = length × breath
Calculation
The garden EFGH is shown in the figure. Where EF = 220 meters & EH = 70 meters.
The width of the path is 4 meters.
Now the area of the path leaving the four colored corners
= [2 × (220 × 4)] + [2 × (70 × 4)]
= (1760 + 560) square meter
= 2320 square meters
Now, the area of 4 square colored corners:
4 × (4 × 4)
{∵ Side of each square = 4 meter}
= 64 square meter
The total area of the path = the area of the path leaving the four colored corners + square colored corners
⇒ Total area of the path = 2320 + 64 = 2384 square meter
∴ Option 4 is the correct answer.
In an election between two candidates, the winning candidate got 70 percent votes of the valid votes and he won by a majority of 3630 votes. If out of total votes polled 75 percent votes are valid, then what is the total number of votes polled?
Answer (Detailed Solution Below)
Quantitative Aptitude Question 10 Detailed Solution
Download Solution PDFGiven:
Valid votes = 75% of total votes
Winning Candidate = 70% of Valid votes
He won by a majority of 3630 votes
Losing Candidate = 30% of Valid votes
Calculation:
Let 100x be the total number of votes polled
Valid votes = 75% of total votes
= 0.75 × 100x
= 75x
Majority of the Winning Candidate is 3630
Then, Difference between Winning and Losing Candidate = (70 % - 30 %) of valid votes
= 40% of the valid votes
Valid Votes = 75x
Then,
= 0.40 × 75x
= 30x
Hence, 30x is Majority of winning candidate
30x = 3630
x = 121
Total number of votes is 100x
= 100 × 121
= 12100
Answer is 12100.
Which of the following number is largest among all?
Answer (Detailed Solution Below)
Quantitative Aptitude Question 11 Detailed Solution
Download Solution PDFConcebt used
a.b̅ = a.bbbbbb
a.0b̅ = a.0bbbb
Calculation
0.7 = 0.700000 ̇....
Now, 0.7777… or
A train of length 400 m takes 15 seconds to cross a train of length 300 m traveling at 60 km per hour from the opposite direction along a parallel track. What is the speed of the longer train, in km per hour?
Answer (Detailed Solution Below)
Quantitative Aptitude Question 12 Detailed Solution
Download Solution PDFGiven
Length of first train (L1) = 400 m
Length of second train (L2) = 300 m
Speed of second train (S2) = 60 km/hr
Time taken to cross each other (T) = 15 s
Concept:
Relative speed when two objects move in opposite directions is the sum of their speeds.
Calculations:
Let the speed of the first train = x km/hr
Total length = 300 + 400
Time = 15 sec
According to the question:
700/15 = (60 + x) × 5/18
28 × 6 = 60 + x
x = 108 km/hr.
Therefore, the speed of the longer train is 108 km per hour.
If the price of petrol has increased from Rs. 40 per litre to Rs. 60 per litre, by how much percent a person has to decrease his consumption so that his expenditure remains same.
Answer (Detailed Solution Below)
Quantitative Aptitude Question 13 Detailed Solution
Download Solution PDFGIVEN :
If the price of petrol has increased from Rs. 40 per litre to Rs. 60 per litre
CALCULATION :
Let the consumption be 100 litres.
When price is Rs. 40 per litres, then, the expenditure = 100 × 40
⇒ Rs. 4,000.
At Rs. 60 per litre, the 60 × consumption = 4000
Consumption = 4,000/60 = 66.67 litres.
∴ Required decreased % = 100 - 66.67 = 33.33%
u : v = 4 : 7 and v : w = 9 : 7. If u = 72, then what is the value of w?
Answer (Detailed Solution Below)
Quantitative Aptitude Question 14 Detailed Solution
Download Solution PDFGiven:
u : v = 4 : 7 and v : w = 9 : 7
Concept Used: In this type of question, number can be calculated by using the below formulae
Calculation:
u : v = 4 : 7 and v : w = 9 : 7
To make ratio v equal in both cases
We have to multiply the 1st ratio by 9 and 2nd ratio by 7
u : v = 9 × 4 : 9 × 7 = 36 : 63 ----(i)
v : w = 9 × 7 : 7 × 7 = 63 : 49 ----(ii)
Form (i) and (ii), we can see that the ratio v is equal in both cases
So, Equating the ratios we get,
u ∶ v ∶ w = 36 ∶ 63 ∶ 49
⇒ u ∶ w = 36 ∶ 49
When u = 72,
⇒ w = 49 × 72/36 = 98
∴ Value of w is 98
What is the value of
Answer (Detailed Solution Below)
Quantitative Aptitude Question 15 Detailed Solution
Download Solution PDFSolution:
= 25/2 + 37/3 + 73/6
= (75 + 74 + 73)/6
= 222/6
= 37
Shortcut Trick
= 12 + 12 + 12 + (1/2 + 1/3 + 1/6)
= 36 + 1 = 37