Quantitative Aptitude MCQ Quiz - Objective Question with Answer for Quantitative Aptitude - Download Free PDF
Last updated on Jun 11, 2025
Latest Quantitative Aptitude MCQ Objective Questions
Quantitative Aptitude Question 1:
The smallest number of two numbers (LCM) is 48 and their maximum consonant (HCF) is 8. Find a second number given the second number if first number is 16.
Answer (Detailed Solution Below)
Quantitative Aptitude Question 1 Detailed Solution
Given:
The smallest number of two numbers (LCM) is 48 and their maximum consonant (HCF) is 8. The first number is 16.
Formula Used:
The relationship between LCM, HCF, and the two numbers (a) and (b) is given by:
Calculation:
Given LCM = 48, HCF = 8, and the first number a = 16 .
Let the second number be b.
⇒
⇒
⇒
⇒
∴ The correct answer is 24.
Quantitative Aptitude Question 2:
Five years ago, the average age of Puneet and Amrita was 15 years. Today the average age of Puneet, Amrita and Renu is 20 years. What will be the age of Renu after 12 years?
Answer (Detailed Solution Below)
Quantitative Aptitude Question 2 Detailed Solution
Given:
Five years ago, the average age of Puneet and Amrita was 15 years.
Today the average age of Puneet, Amrita and Renu is 20 years.
Formula used:
Average × number of observation = sum of observation
Calculations:
When, average of Puneet and Amrita before 5 years ago was 15,
Puneet - 5 + Amrita - 5 = 15 × 2
=> Puneet + Amrita = 30 + 5 + 5
=> Puneet + Amrita = 40
Now, again, when average of the three = 20
Puneet + Amrita + Renu = 20 × 3 = 60
=> Renu = 60 - 40 = 20 (putting the summation of Puneet and Amrita)
Required age of Renu after 12 years = 20 + 12 = 32 years
∴ The answer is 32 years.
Quantitative Aptitude Question 3:
10th class of 40 students took a Maths test. 25 students had an average score of 60. The other students had an average score of 80. What is the average score of the whole class?
Answer (Detailed Solution Below)
Quantitative Aptitude Question 3 Detailed Solution
Given:
Total number of students = 40
25 students had an average score = 60
15 students had an average = 80
Concept used:
Average score of N students = Sum of score of N students/N
Calculation:
According to the question:
⇒ (25 × 60 + 15 × 80)/40
⇒ (1500 + 1200)/40
⇒ 2700/40
⇒ 270/4 = 67.5
∴ The correct answer is 67.5.
Quantitative Aptitude Question 4:
What is
Answer (Detailed Solution Below)
Quantitative Aptitude Question 4 Detailed Solution
Concept Used:
Calculation:
Similarly,
putting the values in the equation,
⇒ (√10 - √9) + (√11 - √10) + (√12 -√11) + ................ + (√196 - √195)
⇒ (-√9 + √196)
⇒ (-3 + 14) = 11
∴ The value of this expression is 11
Quantitative Aptitude Question 5:
A, B, and C have salaries in the ratio 2 ∶ 3 ∶ 5 in the year 2018. In 2019 they got an increment of 10%, 15% and 20%, respectively. In 2020 only A got an increment of 20%. What is the ratio of their salaries in 2020?
Answer (Detailed Solution Below)
Quantitative Aptitude Question 5 Detailed Solution
Given:
The ratio of Salaries of A, B and C in 2018 = 2 ∶ 3 ∶ 5
Increment in salary of A = 10%
Increment in salary of B = 15%
Increment in salary of C = 20%
Formula used:
Salary after increment = old salary × [(100 + increased percent)/100]
Calculation:
Let the salary of A, B and C is 2x, 3x and 5x respectively.
In 2019,
New salary of A after increment = 2x × (110/100) = 220x/100
New salary of B after increment = 3x × (115/100) = 345x/100
New salary of C after increment = 5x × (120/100) = 600x/100
Now, Ratio of the salaries of A, B and C = 220x ∶ 345x ∶ 600x
Now, in 2020, only A got an increment
⇒ (220x/100) × (120/100) = 264x/100
So, the ratio of their salaries in 2020
⇒ A : B : C = 264x/100 : 345x/100 : 600x/100
⇒ A : B : C = 264 : 345 : 600
⇒ A : B : C = 88 ∶ 115 ∶ 200
∴ The new ratio of salaries of A, B and C is 88 ∶ 115 ∶ 200 respectively.
Shortcut Trick
Top Quantitative Aptitude MCQ Objective Questions
If x −
Answer (Detailed Solution Below)
Quantitative Aptitude Question 6 Detailed Solution
Download Solution PDFGiven:
x - 1/x = 3
Concept used:
a3 - b3 = (a - b)3 + 3ab(a - b)
Calculation:
x3 - 1/x3 = (x - 1/x)3 + 3 × x × 1/x × (x - 1/x)
⇒ (x - 1/x)3 + 3(x - 1/x)
⇒ (3)3 + 3 × (3)
⇒ 27 + 9 = 36
∴ The value of x3 - 1/x3 is 36.
Alternate Method If x - 1/x = a, then x3 - 1/x3 = a3 + 3a
Here a = 3
x - 1/x3 = 33 + 3 × 3
= 27 + 9
= 36
A shopkeeper earns a profit of 25 percent on selling a radio at 15 percent discount on the Printed price. Finds the ratio of the Printed price and the cost price of the radio.
Answer (Detailed Solution Below)
Quantitative Aptitude Question 7 Detailed Solution
Download Solution PDFGiven:
Profit = 25 Percent
Discount = 15 Percent
Formula:
MP/CP = (100 + Profit %)/(100 – Discount %)
MP = Printed Price
CP = Cost Price
Calculation:
We know that –
MP/CP = (100 + Profit %)/(100 – Discount %) ………. (1)
Put all given values in equation (1) then we gets
MP/CP = (100 + 25)/(100 – 15)
⇒ 125/85
⇒ 25/17
∴ The Ratio of the Printed price and cost price of radio will be 25 ∶ 17Six chords of equal lengths are drawn inside a semicircle of diameter 14√2 cm. Find the area of the shaded region?
Answer (Detailed Solution Below)
Quantitative Aptitude Question 8 Detailed Solution
Download Solution PDFGiven:
Diameter of semicircle = 14√2 cm
Radius = 14√2/2 = 7√2 cm
Total no. of chords = 6
Concept:
Since the chords are equal in length, they will subtend equal angles at the centre. Calculate the area of one sector and subtract the area of the isosceles triangle formed by a chord and radius, then multiply the result by 6 to get the desired result.
Formula used:
Area of sector = (θ/360°) × πr2
Area of triangle = 1/2 × a × b × Sin θ
Calculation:
The angle subtended by each chord = 180°/no. of chord
⇒ 180°/6
⇒ 30°
Area of sector AOB = (30°/360°) × (22/7) × 7√2 × 7√2
⇒ (1/12) × 22 × 7 × 2
⇒ (77/3) cm2
Area of triangle AOB = 1/2 × a × b × Sin θ
⇒ 1/2 × 7√2 × 7√2 × Sin 30°
⇒ 1/2 × 7√2 × 7√2 × 1/2
⇒ 49/2 cm2
∴ Area of shaded region = 6 × (Area of sector AOB - Area of triangle AOB)
⇒ 6 × [(77/3) – (49/2)]
⇒ 6 × [(154 – 147)/6]
⇒ 7 cm2
∴ Area of shaded region is 7 cm2
There is a rectangular garden of 220 metres × 70 metres. A path of width 4 metres is built around the garden. What is the area of the path?
Answer (Detailed Solution Below)
Quantitative Aptitude Question 9 Detailed Solution
Download Solution PDFFormula used
Area = length × breath
Calculation
The garden EFGH is shown in the figure. Where EF = 220 meters & EH = 70 meters.
The width of the path is 4 meters.
Now the area of the path leaving the four colored corners
= [2 × (220 × 4)] + [2 × (70 × 4)]
= (1760 + 560) square meter
= 2320 square meters
Now, the area of 4 square colored corners:
4 × (4 × 4)
{∵ Side of each square = 4 meter}
= 64 square meter
The total area of the path = the area of the path leaving the four colored corners + square colored corners
⇒ Total area of the path = 2320 + 64 = 2384 square meter
∴ Option 4 is the correct answer.
In an election between two candidates, the winning candidate got 70 percent votes of the valid votes and he won by a majority of 3630 votes. If out of total votes polled 75 percent votes are valid, then what is the total number of votes polled?
Answer (Detailed Solution Below)
Quantitative Aptitude Question 10 Detailed Solution
Download Solution PDFGiven:
Valid votes = 75% of total votes
Winning Candidate = 70% of Valid votes
He won by a majority of 3630 votes
Losing Candidate = 30% of Valid votes
Calculation:
Let 100x be the total number of votes polled
Valid votes = 75% of total votes
= 0.75 × 100x
= 75x
Majority of the Winning Candidate is 3630
Then, Difference between Winning and Losing Candidate = (70 % - 30 %) of valid votes
= 40% of the valid votes
Valid Votes = 75x
Then,
= 0.40 × 75x
= 30x
Hence, 30x is Majority of winning candidate
30x = 3630
x = 121
Total number of votes is 100x
= 100 × 121
= 12100
Answer is 12100.
Which of the following number is largest among all?
Answer (Detailed Solution Below)
Quantitative Aptitude Question 11 Detailed Solution
Download Solution PDFConcebt used
a.b̅ = a.bbbbbb
a.0b̅ = a.0bbbb
Calculation
0.7 = 0.700000 ̇....
Now, 0.7777… or
A train of length 400 m takes 15 seconds to cross a train of length 300 m traveling at 60 km per hour from the opposite direction along a parallel track. What is the speed of the longer train, in km per hour?
Answer (Detailed Solution Below)
Quantitative Aptitude Question 12 Detailed Solution
Download Solution PDFGiven
Length of first train (L1) = 400 m
Length of second train (L2) = 300 m
Speed of second train (S2) = 60 km/hr
Time taken to cross each other (T) = 15 s
Concept:
Relative speed when two objects move in opposite directions is the sum of their speeds.
Calculations:
Let the speed of the first train = x km/hr
Total length = 300 + 400
Time = 15 sec
According to the question:
700/15 = (60 + x) × 5/18
28 × 6 = 60 + x
x = 108 km/hr.
Therefore, the speed of the longer train is 108 km per hour.
If the price of petrol has increased from Rs. 40 per litre to Rs. 60 per litre, by how much percent a person has to decrease his consumption so that his expenditure remains same.
Answer (Detailed Solution Below)
Quantitative Aptitude Question 13 Detailed Solution
Download Solution PDFGIVEN :
If the price of petrol has increased from Rs. 40 per litre to Rs. 60 per litre
CALCULATION :
Let the consumption be 100 litres.
When price is Rs. 40 per litres, then, the expenditure = 100 × 40
⇒ Rs. 4,000.
At Rs. 60 per litre, the 60 × consumption = 4000
Consumption = 4,000/60 = 66.67 litres.
∴ Required decreased % = 100 - 66.67 = 33.33%
u : v = 4 : 7 and v : w = 9 : 7. If u = 72, then what is the value of w?
Answer (Detailed Solution Below)
Quantitative Aptitude Question 14 Detailed Solution
Download Solution PDFGiven:
u : v = 4 : 7 and v : w = 9 : 7
Concept Used: In this type of question, number can be calculated by using the below formulae
Calculation:
u : v = 4 : 7 and v : w = 9 : 7
To make ratio v equal in both cases
We have to multiply the 1st ratio by 9 and 2nd ratio by 7
u : v = 9 × 4 : 9 × 7 = 36 : 63 ----(i)
v : w = 9 × 7 : 7 × 7 = 63 : 49 ----(ii)
Form (i) and (ii), we can see that the ratio v is equal in both cases
So, Equating the ratios we get,
u ∶ v ∶ w = 36 ∶ 63 ∶ 49
⇒ u ∶ w = 36 ∶ 49
When u = 72,
⇒ w = 49 × 72/36 = 98
∴ Value of w is 98
What is the value of
Answer (Detailed Solution Below)
Quantitative Aptitude Question 15 Detailed Solution
Download Solution PDFSolution:
= 25/2 + 37/3 + 73/6
= (75 + 74 + 73)/6
= 222/6
= 37
Shortcut Trick
= 12 + 12 + 12 + (1/2 + 1/3 + 1/6)
= 36 + 1 = 37