Sewage Treatment MCQ Quiz - Objective Question with Answer for Sewage Treatment - Download Free PDF

Last updated on Mar 28, 2025

Latest Sewage Treatment MCQ Objective Questions

Sewage Treatment Question 1:

Imhoff tank results in ______ removal of solids and _______ removal of BOD.

  1. 30 - 40 %, 60 - 65 %
  2. 60 - 65 %, ​ 30 - 40 %
  3.  60 - 70 %, 98 - 99 %
  4. 20 - 30 %, 60 - 70 %
  5. 30 - 40 %, ​ 10 - 20 %

Answer (Detailed Solution Below)

Option 2 : 60 - 65 %, ​ 30 - 40 %

Sewage Treatment Question 1 Detailed Solution

Explanation:

Imhoff tank results in 60 - 65 % removal of solids and 30 - 40 % removal of BOD.

Imhoff tank:

  • An Imhoff tank is an improvement over the septic tank in which the incoming sewage is not allowed to get mixed up with the sludge produced and the outgoing effluent is not allowed to carry with it a large amount of organic load, as in the case of the septic tank.
  • Imhoff tanks combine the advantages of both the septic as well as sedimentation tanks.
  • An Imhoff tank is two storey tank in which the upper chamber served as sedimentation (aerobic condition) and the lower chamber served as digestion chamber (anaerobic condition).
  • They find use in case of small treatment plants requiring only primary treatment.
  • They are quite economical and do not require skilled attention during operations.
  • The result obtained is quite good, with 60 to 65 % removal of solids and 30 to 40 % removal of BOD.
  • There is no problem of sludge disposal, as in the case of sedimentation tan

Sewage Treatment Question 2:

Waste stabilization ponds can be:-

  1. Aerobic
  2. Anaerobic
  3. Facultative
  4. Any one of the above
  5. None of the above

Answer (Detailed Solution Below)

Option 4 : Any one of the above

Sewage Treatment Question 2 Detailed Solution

Wastewater Stabilization Ponds (WSPs)/Oxidation pond:

It is also called lagoons or stabilization ponds, are large, shallow ponds designed to treat wastewater through the interaction of sunlight bacteria, and algae. Algae grow using energy from the sun and carbon dioxide and inorganic compounds released by bacteria in water.

During the process of photosynthesis, the algae release oxygen needed by aerobic bacteria. Mechanical aerators are sometimes installed to supply yet more oxygen, thereby reducing the required size of the pond. Sludge deposits in the pond must eventually be removed by dredging.

Algae remaining in the pond effluent can be removed by filtration or by a combination of chemical treatment and settling.

The ponds can be used individually or linked in a series for improved treatment. There are three types of ponds, (1) anaerobic, (2) facultative, and (3) aerobic (maturation), each with different treatment and design characteristics.

RRB JE CE R 24 14Q Environmental Engineering Subject Test Part 2(Hindi) Nitesh Madhushri D3

Sewage Treatment Question 3:

P. Trickling filter consists of a bed of crushed stone, gravel or slag of relatively large size.

Q. As sewage passes through the filtering media of the trickling filter, an organic film is formed around the particles of filtering media.

Identify the correct option.

  1. P is correct and Q is incorrect
  2. P is incorrect and Q is correct
  3. Both are incorrect
  4. Both are correct
  5. Insufficient Information

Answer (Detailed Solution Below)

Option 4 : Both are correct

Sewage Treatment Question 3 Detailed Solution

Concept:

Trickling Filters:

  • A trickling filter is an attached growth process i.e. process in which microorganisms responsible for treatment are attached to inert packing material.
  • The packing material used in attached growth processes includes rock, gravel, slag, sand, redwood, and a wide range of plastic and other synthetic materials.

F1 A.M Madhu 14.04.20 D12

Figure: Trickling Filter

The process of trickling filter is as follows:

  • The wastewater in the trickling filter is distributed over the top area of a vessel containing non-submerged packing material.
  • Air circulation in the void space, by either natural draft or blowers, provides oxygen for the microorganisms growing as an attached biofilm.
  • During operation, the organic material present in the wastewater is metabolized by the biomass attached to the medium. The biological slime grows in thickness as the organic matter abstracted from the flowing wastewater is synthesized into new cellular material.
  • The thickness of the aerobic layer is limited by the depth of penetration of oxygen into the microbial layer.
  • The micro-organisms near the medium face enter the endogenous phase as the substrate is metabolized before it can reach the micro-organisms near the medium face as a result of increased thickness of the slime layer and lose their ability to cling to the media surface.
  • The liquid then washes the slime off the medium and a new slime layer starts to grow. This phenomenon of losing the slime layer is called sloughing.
  • The sloughed-off film and treated wastewater are collected by an under drainage which also allows circulation of air through the filter.
  • The collected liquid is passed to a settling tank used for solid-liquid separation.

Sewage Treatment Question 4:

Which of the following statements is/are correct in relation to sedimentation with coagulation?

1. Coagulation is usually found necessary for water having turbidity greater than 30-50 ppm.

2. Alum produces heavy floc compared with iron salt coagulants.

3. It is difficult to dewater the sludge formed by alum coagulant.

  1. Statements 1 and 2 are correct, while statement 3 is incorrect.
  2. Statement 1 is correct, while statements 2 and 3 are incorrect. 
  3. Statement 1 is incorrect, while statements 2 and 3 are correct.
  4. Statements 1 and 3 are correct, while statement 2 is incorrect.

Answer (Detailed Solution Below)

Option 4 : Statements 1 and 3 are correct, while statement 2 is incorrect.

Sewage Treatment Question 4 Detailed Solution

Explanation:

Sedimentation with Coagulation

Sedimentation with coagulation is a water treatment process used to remove suspended solids from water by adding a coagulant to form flocs, which then settle out of the water.

Analyzing the Given Statements

  1. Statement 1: "Coagulation is usually found necessary for water having turbidity greater than 30-50 ppm." (Correct)

    • Coagulation is typically required for water with higher turbidity levels to effectively remove suspended particles.

  2. Statement 2: "Alum produces heavy floc compared with iron salt coagulants." (Incorrect)

    • Iron salt coagulants tend to produce heavier and more compact flocs compared to alum.

  3. Statement 3: "It is difficult to dewater the sludge formed by alum coagulant." (Correct)

    • The sludge formed by alum coagulant has a gelatinous nature, making it more challenging to dewater compared to other coagulants.

Sewage Treatment Question 5:

As per Central Public Health and Environmental Engineering Organization (CPHEEO), the minimum velocity at ultimate peak flow and maximum velocity of flow to be adopted in the design of gravity sewers shall be respectively : 

  1. 0.4 m/s and 2.0 m/s 
  2. 0.6 m/s and 3.5 m/s 
  3. 0.8 m/s and 3 m/s 
  4. 0.45 m/s and 1.5 m/s
  5. 1.6 m/s and 6 m/s 

Answer (Detailed Solution Below)

Option 3 : 0.8 m/s and 3 m/s 

Sewage Treatment Question 5 Detailed Solution

Explanation: 

(i) To ensure that deposition of suspended solids does not take place, self-cleansing velocities using Shield's formula is considered in the design of sewers.

    \(V_{sc}=\sqrt{\frac{8k}{f}\left ( G-1 \right )gd}\)

Where K is a constant that depend upon the type of solids present in the sewage
f = Friction factor

(ii) The above formula indicates that the velocity required to transport material in sewers is mainly dependent on the particle size and specific gravity and slightly dependent on conduit shape and depth of flow.

The specific gravity of grit is usually in the range of 2.4 to 2.65. Gravity sewers shall be designed for the velocities as given in Table below:

Criteria Value
Minimum velocity at initial peak flow 0.6 m/s
Minimum velocity at ultimate peak flow 0.8
m/s
Maximum velocity 3 m/s

Top Sewage Treatment MCQ Objective Questions

The activated sludge process is an

  1. Aerobic attached growth system
  2. Anaerobic attached growth system
  3. Anaerobic suspended growth system
  4. Aerobic suspended system

Answer (Detailed Solution Below)

Option 4 : Aerobic suspended system

Sewage Treatment Question 6 Detailed Solution

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Explanation:

Activated sludge process:

  • The essential features of the activated sludge process are an aeration stage, solids-liquid separation following aeration, and a sludge recycle system.
  • Wastewater after primary treatment enters an aeration tank where the organic matter is brought into intimate contact with the sludge from the secondary clarifier.
  • It requires less space, does not produce obnoxious odor, and requires less time for wastewater treatment.
  • It requires skilled supervision


Followings are the classification of secondary treatment units:

Method

Contact Mechanism

Decomposition

Trickling filter

Attached growth

Aerobic

Rotating biological contactor

Attached growth

Aerobic

Activated sludge process

 

Suspended growth

Aerobic

Oxidation pond

Suspended growth

Aerobic

Septic tank

Suspended growth

Anaerobic

Imhoff tank

Suspended growth

Anaerobic

Match List - I with List-II and select the correct answer using the codes given below the lists:

List - I

(Treatment Unit)

List - II

(Detention Time)

A. Grit chamber

i. Six hours

B. Primary sedimentation

ii. Two minutes

C. Activated sludge

iii. Two hours

D. Sludge digestion

iv. Twenty days

  1. A - iii, B - i, C - iv, D - ii
  2. A - ii, B - iii, C - i, D - iv
  3. A - ii, B - i, C - iii, D - iv
  4. A - i, B - ii, C - iii, D - iv

Answer (Detailed Solution Below)

Option 2 : A - ii, B - iii, C - i, D - iv

Sewage Treatment Question 7 Detailed Solution

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Explanation:

Detention time for different type of Treatment unit

Treatment Unit

Detention time

Grit chamber

30-60 second

Primary sedimentation

2-2.5 hour

Sludge digestion

20-30 days

Activated sludge process

2-4 hour

Oxidation pond

2-6 weeks

Septic tank

12-36 hour

 

Note: Septic tank has high detention time whereas Grit chamber has less detention time.

What will be the Sludge Volume Index (SVI) (ml/gram) if 100 ml of sludge collected in 30 mins on drying weighs 800 mg?

  1. 125
  2. 8
  3. 0.008
  4. 0.125

Answer (Detailed Solution Below)

Option 1 : 125

Sewage Treatment Question 8 Detailed Solution

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Concept:

Sludge volume index is the volume occupied in mL by one gm of solids in the mixed liquor after settling for 30 minutes.

The recommended value of the Sludge Volume Index (SVI) for municipal sewage is approximately lying in the range of 80 to 150.

\({\rm{Sludge\;volume\;index}} = \frac{{{\rm{Volume\;of\;settled\;sludge\;in\;ml}}}}{{{\rm{MLSS\;present}}}}\)

Calculation:

Given,

Volume of settled sludge = 100 ml, Drying weight (MLSS) = 800 mg

\(\rm SVI = \frac{{100}}{{800 \ \times \ {{10}^{ - 3}}}}\ ml/gram\)

SVI = 125 ml/gram

A ______ tank is an underground chamber made of concrete, fiberglass, or plastic through which domestic wastewater (sewage) flows for basic treatment.

  1. soap
  2. pressure
  3. flush
  4. septic

Answer (Detailed Solution Below)

Option 4 : septic

Sewage Treatment Question 9 Detailed Solution

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The correct answer is septic.

Key Points

  • A septic tank is concrete, fibreglass, or plastic subterranean chamber through which domestic wastewater (sewage) flows for basic treatment.
  • Anaerobic action occurs within the septic tank. The term "septic" refers to the anaerobic bacterial environment that forms in the tank and decomposes the waste that is expelled.
  • Domestic sewage, as well as animal and poultry wastes, are examples of N-rich materials that supply nutrients for anaerobic organism development and multiplication.

Important Points

  • A pressure/vacuum vent is installed in pressure tanks to avoid venting loss due to boiling and breathing loss due to daily temperature or barometric pressure variations. 

What will be the Sludge Volume Index (SVI) if 100 ml of sludge collected in 30 mins on drying weighs 800 mg?

  1.  115
  2. 78
  3. 125
  4. 100

Answer (Detailed Solution Below)

Option 3 : 125

Sewage Treatment Question 10 Detailed Solution

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Concept:

Sludge volume index is the volume occupied in mL by one gm of solids in the mixed liquor after settling for 30 minutes.

The recommended value of the Sludge Volume Index (SVI) for municipal sewage is approximately lies in the range of 80 to 150.

\({\rm{Sludge\;volume\;index}} = \frac{{{\rm{Volume\;of\;settled\;sludge\;in\;ml}}}}{{{\rm{MLSS\;present}}}}\)

Calculation:

Given,

Volume of settled sludge = 100 ml, Drying weight (MLSS) = 800 mg

\(\rm SVI = \frac{{100}}{{800 \ \times \ {{10}^{ - 3}}}}\ ml/gram\)

SVI = 125 ml/gram

In which of the following wastewater treatment units is organic matter destroyed and stabilised by anaerobic bacteria?

  1. Trickling filter
  2. Oxidation pond
  3. Sedimentation tank
  4. Septic tank

Answer (Detailed Solution Below)

Option 4 : Septic tank

Sewage Treatment Question 11 Detailed Solution

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Concept:

A septic tank is an underground chamber made of concrete, fiberglass or plastic through which domestic wastewater (sewage) flows for basic treatment. Action within the septic tank is anaerobic in nature.

The term "septic" refers to the anaerobic bacterial environment that develops in the tank which decomposes the waste discharged into the tank.

Followings are the classification of secondary treatment units

S.No.

Method

Contact Mechanism

Decomposition

1

Trickling filter

Attached growth

Aerobic

2

Rotating biological contactor

Attached growth

Aerobic

3

Activated sludge process

Suspended growth

Aerobic

4

Oxidation pond

Suspended growth

Aerobic

5

Septic tank

Suspended growth

Anaerobic

6

Imhoff tank

Suspended growth

Anaerobic

Aerobic attached growth process is classified under:

  1. Activated sludge process
  2. Chemical clarification 
  3. Preliminary treatment
  4. Biological treatment

Answer (Detailed Solution Below)

Option 4 : Biological treatment

Sewage Treatment Question 12 Detailed Solution

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Explanation:

Treatment units Aerobic Anaerobic
Based on an attached growth system

1. Trickling Filter

2. Rotatory Biological Contactor

 
Based on a suspended growth system

1. Activated Sludge Process

2. Oxidation Pond

1. Upflow Anaerobic Sludge Blanket Reactor

2. Septic Tank

3. Imhoff Tank

Which of the given options is NOT a part of the preliminary treatment of sewage?

  1. Sedimentation tanks
  2. Screening
  3. Grit chambers
  4. Skimming tanks

Answer (Detailed Solution Below)

Option 1 : Sedimentation tanks

Sewage Treatment Question 13 Detailed Solution

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Explanation:

The four processes of wastewater treatment are:

1. Preliminary Treatment

  • Screening, grit chambers, and skimming tanks.

Note:

In Preliminary Treatment:

  • Oils and greases are removed by skimming tanks.
  • Floating materials are removed by screening.
  • Grit and sand are removed by grit chambers

2. Primary Treatment

  • Sedimentation (basically involves the process of sedimentation or settling),
  • Chemical-aided Sedimentation

3. Secondary or Biological Treatment

  • Activated sludge process
  • Aerated lagoons         
  • Sequencing batch reactor
  • Aerobic digestion
  • Trickling filters
  • Rotating biological contractors

4. Tertiary or Advanced Treatment

  • Solids removal
  • Biological nitrogen removal
  • Biological phosphorus removal
  • Disinfection.

Study the given statements with respect to soak pits and choose the correct option.

1. Soak pits are preferable at locations, where the water table level is high.

2. Soak pits are preferable at locations where soil is porous.

  1. Both the statement are true
  2. Statement 1 is false and statement 2 is true
  3. Statement 1 is true and statement 2 is false
  4. Both the statements are false

Answer (Detailed Solution Below)

Option 2 : Statement 1 is false and statement 2 is true

Sewage Treatment Question 14 Detailed Solution

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Explanation:

Soak pit: 

  • A soak pit, also known as a soakaway or leach pit, is a covered, porous-walled chamber that allows water to slowly soak into the ground.
  • A soak pit is a covered, porous-walled chamber that allows water to slowly soak into the ground and also known as a soakaway or leach pit, and the pre-settled sewage from the septic tank is release to the underground chamber from where it infiltrates into the neighboring soils.
  • So soak pits are preferred where the soil is porous in nature.

The Hydraulic loading for a High Rate Trickling Filter varies between

  1. 110 to 330 M.L per hectare per day
  2. 50 to 60 M.L per hectare per day
  3. 500 to 600 M.L per hectare per day
  4. 11 to 33 M.L per hectare per day

Answer (Detailed Solution Below)

Option 1 : 110 to 330 M.L per hectare per day

Sewage Treatment Question 15 Detailed Solution

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Explanation:

A trickling filter is a wastewater treatment system that removes organic matter from wastewater. It is an Aerobic attached growth system

        Parameters             Standard rate trickling filter High-rate trickling filter
Hydraulic loading rate (M.L/ hectare/day)
10-40 100-400

Organic Loading rate  (Kg BOD/m3/day)

0.11-0.37 0.37-1.85

Depth (m)

1.5-3.0 1.0-2.0
 Recirculation Ratio 0 1.0-4.0

 

From the above table, we can see that the most suitable option will be option A ie 110 - 330 ML per hectare per day

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