Biomolecules MCQ Quiz in मल्याळम - Objective Question with Answer for Biomolecules - സൗജന്യ PDF ഡൗൺലോഡ് ചെയ്യുക

Last updated on Mar 18, 2025

നേടുക Biomolecules ഉത്തരങ്ങളും വിശദമായ പരിഹാരങ്ങളുമുള്ള മൾട്ടിപ്പിൾ ചോയ്സ് ചോദ്യങ്ങൾ (MCQ ക്വിസ്). ഇവ സൗജന്യമായി ഡൗൺലോഡ് ചെയ്യുക Biomolecules MCQ ക്വിസ് പിഡിഎഫ്, ബാങ്കിംഗ്, എസ്എസ്‌സി, റെയിൽവേ, യുപിഎസ്‌സി, സ്റ്റേറ്റ് പിഎസ്‌സി തുടങ്ങിയ നിങ്ങളുടെ വരാനിരിക്കുന്ന പരീക്ഷകൾക്കായി തയ്യാറെടുക്കുക

Latest Biomolecules MCQ Objective Questions

Top Biomolecules MCQ Objective Questions

Biomolecules Question 1:

Given below are two statements :

Statement I: A unit formed by the attachment of a base to 1' position of sugar is known as nucleoside

Statement II: When nucleoside is linked to phosphorous acid at 5 '-position of sugar moiety, we get nucleotide.

In the light of the above statements, choose the correct answer from the options given below:

  1. Both Statement I and Statement II are true.
  2. Both Statement I and Statement II are false.
  3. Statement l is true but Statement II is false.
  4. Statement l is false but Statement ll is true.

Answer (Detailed Solution Below)

Option 3 : Statement l is true but Statement II is false.

Biomolecules Question 1 Detailed Solution

Explanation:-

  • Statement I: A unit formed by the attachment of a base to 1' position of sugar is known as nucleoside.
    • This statement is correct. A nucleoside consists of a nitrogenous base attached to the 1' position of a sugar molecule (either ribose or deoxyribose).
  • Statement II: When nucleoside is linked to phosphorous acid at 5'-position of sugar moiety, we get nucleotide.
    • This statement is incorrect. A nucleoside becomes a nucleotide when it is linked to a phosphate group at the 5'-position of the sugar, not phosphorous acid.

CONCLUSION:
The correct answer is Statement I is true but Statement II is false.

Biomolecules Question 2:

Which of the following vitamin is most easily destroyed vitamin while cooking?

  1. Vitamin B12
  2. Vitamin A
  3. Vitamin B4
  4. Vitamin C
  5. None of the above/More than one of the above.

Answer (Detailed Solution Below)

Option 4 : Vitamin C

Biomolecules Question 2 Detailed Solution

The correct answer is Vitamin C.

Concept:

  • Vitamins are organic substances that we need in sufficient quantities to maintain good health.
  • Our body, however, cannot synthesize them. Therefore, we need to consume natural sources such as fruits and vegetables.
  • Vitamins are divided into two groups– water-soluble vitamins (Vitamins of B group and Vitamin C) and fat-soluble vitamins (Vitamins A, D, E, and K).

Explanation:

  • Vitamin C is the vitamin that is destroyed by heat during cooking. When we boil something that contains vitamin C, it reduces its content more than any other method of cooking.
  • Broccoli, spinach, and lettuce, for example, lose up to or more than 50% of their vitamin C when they are cooked.
  • Water-soluble vitamins are also temperature-sensitive vitamins.
  • When the temperature drops below 860F, vitamin C begins to denature. 
  • Vitamin C is primarily found in oranges, strawberries, tomatoes, broccoli, and green peppers, among other fruits and vegetables. 
  • When vitamin C is exposed to air, it is easily destroyed, which is what happens when food is overheated.
  • When fat-soluble vitamins are heated or exposed to air, they are not destroyed

Mistake Points 

vitamin C and vitamin B12 are sensitive to heat, vitamin C is generally considered more easily destroyed by cooking compared to vitamin B12. Vitamin B12 is also sensitive to heat, but it tends to be more stable during cooking than vitamin C. So, if you're looking for the most easily destroyed vitamin while cooking, it's typically vitamin C.

Biomolecules Question 3:

Which of the given statement is INCORRECT about glycogen?

  1. It is a straight chain polymer similar to amylase.
  2. Only α-linkages are present in the molecule.
  3. It is present in animal cells.
  4. It is present in some yeast and fungi.

Answer (Detailed Solution Below)

Option 1 : It is a straight chain polymer similar to amylase.

Biomolecules Question 3 Detailed Solution

Concept:

The structure of glycogen is similar to amylopectin.

It is found in yeast and fungi and stored in any animal body.

It contains α-glycosidic linkages.

Thus, option (a) is the incorrect statement about glycogen.

Biomolecules Question 4:

Which of the following is the correct structure of L-Glucose 

  1. qImage6697de5ebf9ba8880946b801
  2. qImage6697de5fbf9ba8880946b803
  3. qImage6697de5fbf9ba8880946b805
  4. qImage6697de5fbf9ba8880946b827

Answer (Detailed Solution Below)

Option 1 : qImage6697de5ebf9ba8880946b801

Biomolecules Question 4 Detailed Solution

Structure of L-Glucose is
qImage6697de60bf9ba8880946b828

Biomolecules Question 5:

The number of DNA molecules in each chromosome is

  1. one
  2. upto 10
  3. more than hundred
  4. More than one of the above
  5. None of the above

Answer (Detailed Solution Below)

Option 1 : one

Biomolecules Question 5 Detailed Solution

Explanation:

  • A single chromosome contains only one DNA (deoxyribonucleic acid) molecule and so many genes.
  • Humans have 23 pairs of chromosomes.
    • 22 pairs of autosomes chromosomes and one pair of sex chromosomes, X and Y.

Important Points

  • In the cell nucleus, the DNA molecule is packaged into thread-like structures called chromosomes.
    • A chromosome (microscopic structure) is made up of DNA tightly coiled many times around proteins called histones that support its structure.
    • A chromosome has two arm - p arm (short arm) and q arm (long arm), joined in the location of the centromere.

Key Points

  • The information in DNA (double helix structure) is stored as a code made up of four chemical bases: adenine (A), guanine (G), cytosine (C), and thymine (T).
    • DNA has two base pairs, A-T and G-C, attached to a sugar-phosphate backbone.

Biomolecules Question 6:

Identify the correct statement regarding enzymes

  1. Enzymes are specific biological catalysts that cannot be poisoned
  2. Enzymes are normally heterogeneous catalysts that are very specific in their action
  3. Enzymes are specific biological catalysts that can normally function at very high temperature (T~1000K)
  4. Enzymes are specific biological catalysts that possess well-defined active sites

Answer (Detailed Solution Below)

Option 4 : Enzymes are specific biological catalysts that possess well-defined active sites

Biomolecules Question 6 Detailed Solution

Explanation-

⇒ Enzymes can be defined as biological polymers that catalyze biochemical reactions.

⇒ Most enzymes are proteins with catalytic capabilities crucial to performing different processes. Metabolic processes and other chemical reactions in the cell are carried out by a set of enzymes necessary to sustain life.

⇒ Enzymes are a linear chain of amino acids, which give rise to a three-dimensional structure. The sequence of amino acids specifies the structure, which in turn identifies the catalytic activity of the enzyme.

⇒ Upon heating, the enzyme’s structure denatures, resulting in a loss of enzyme activity, which typically is associated with temperature.

⇒ Enzymes are said to possess an active site. The active site is a part of the molecule that has a definite shape and the functional group for the binding of reactant molecules.

⇒ The molecule that binds to the enzyme is referred to as the substrate group. The substrate and the enzyme form an intermediate reaction with low activation energy without any catalysts.

⇒ The effectiveness of a catalyst is maximum at its optimum temperature. The activity of the biochemical catalysts declines at either side of the optimum temperature.

Biomolecules Question 7:

Identify the proteolytic enzyme present in the gastric juice.

  1. Peptidase
  2. Trypsin
  3. Chymotrypsin
  4. Pepsin

Answer (Detailed Solution Below)

Option 4 : Pepsin

Biomolecules Question 7 Detailed Solution

Concept:

  • The proteolytic enzyme pepsin is found in the gastric juice of all vertebrates.
  • The central or the chief cells of the gastric mucosa secrete the inactive precursor pepsinogen which on the cleavage of a peptide inhibitor and other neutral peptides is converted to the proteolytically active pepsin.
  • Proteolytic enzymes help break proteins down into smaller protein fragments called peptides and amino acids.

Biomolecules Question 8:

Which of the following is a polysaccharide ?

  1. Glucose
  2. Galactose
  3. sucrose
  4. Pectines.

Answer (Detailed Solution Below)

Option 4 : Pectines.

Biomolecules Question 8 Detailed Solution

CONCEPT:

Polysaccharides and Other Sugars

  • Monosaccharides are the simplest form of carbohydrates. They are single sugar molecules and serve as the building blocks for more complex carbohydrates. Examples of monosaccharides include glucose and galactose.
  • Disaccharides are carbohydrates composed of two monosaccharides joined by a glycosidic bond. Sucrose is an example of a disaccharide, consisting of one glucose molecule and one fructose molecule.
  • Polysaccharides are complex carbohydrates made up of long chains of monosaccharide units. These polysaccharides perform various functions, such as providing structural support in plants or serving as energy storage molecules. Pectines are an example of a polysaccharide.

EXPLANATION:

  • Glucose is a monosaccharide. It is one of the most important simple sugars in biology, providing energy for cellular activities through processes like glycolysis and cellular respiration.
  • Galactose is also a monosaccharide. It is similar in structure to glucose and is a component of lactose, which is found in milk. Like glucose, it is a simple sugar that plays an important role in energy metabolism.
  • Sucrose is a disaccharide, composed of one molecule of glucose and one molecule of fructose. Sucrose is commonly found in table sugar and serves as a major source of energy in many organisms.
  • Pectines are polysaccharides. They are found in the cell walls of plants, where they play a key role in providing structural integrity. Pectines are also widely used in the food industry as gelling agents in jams, jellies, and other products. As polysaccharides, they consist of long chains of monosaccharide units linked together.
  • Chemical structure of pectines: 

CONCLUSION:

The correct answer is Option 4: Pectines

Biomolecules Question 9:

Glucose is represented by which of the following formulae? 

  1. C6H12O6
  2. C2H5OH
  3. CH3COOH
  4. C6H14O8

Answer (Detailed Solution Below)

Option 1 : C6H12O6

Biomolecules Question 9 Detailed Solution

The correct answer is C6H12O6.Key Points

  • Glucose is represented by C6H12O6.
  • Glucose is a simple sugar and the most important carbohydrate in the body.
  • Glucose is a monosaccharide, which means it is a single sugar molecule.
  • It is a primary source of energy for the body and is used by every cell.
  • Glucose is commonly found in foods such as fruits, vegetables, and grains.
  • When glucose levels in the body are too high, it can lead to health problems such as diabetes.

Additional Information

  • C2H5OH is the formula for ethanol, which is a type of alcohol.
    • Ethanol is a colorless, volatile, flammable liquid with a strong flavor and odor similar to wine.
  • CH3COOH is the formula for acetic acid, which is the main component of vinegar.
    • The distinctive smell of vinegar is caused by the fermentation byproduct known as acetic acid.

Biomolecules Question 10:

In the following structure,

F6 Madhuri Engineering 22.06.2022 D3

anomeric carbon is

  1. 1
  2. 2
  3. 3
  4. 4

Answer (Detailed Solution Below)

Option 1 : 1

Biomolecules Question 10 Detailed Solution

Explanation:

Anomeric carbon-

  • An anomeric carbon is a hemiacetal or hemiketal carbon of cyclic sugar. It is the carbon at which the alpha anomer or beta anomer is formed.
  • An anomeric carbon can be identified as the carbonyl carbon (of the aldehyde or ketone functional group) in the open-chain form of the sugar. It can also be identified as the carbon bonded to the ring oxygen and a hydroxyl group in the cyclic form.
Given data and Analysis:
F6 Madhuri Engineering 22.06.2022 D3
⇒ In the cyclic form of sugar, the anomeric carbon is the carbon that was part of the carbonyl group in the straight-chain structure.
⇒ When the chain converts to a ring, C−1 becomes a chiral center.
⇒ C − 1 is the anomeric carbon.

⇒ C - 1 is an anomeric carbon and due to this, it exists in two forms, α, and β.

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