A 10 hp, 600 rpm DC shunt motor draws a line current of 18 A at 500 V. Determine the efficiency of the motor assuming 1 hp = 735.5 W.

Question

Question

This question was previously asked in

MPPGCL JE Electrical 19 March 2019 Shift 2 Official Paper

Answer 1

Concept

The efficiency of the motor is given by:

% η \(={P_{out}\over P_{in}}× 100\)

Calculation

Given, P_out = 10 × 735.5 = 7355 W

P_in = 500 × 18 = 9000 W

% η \(={P_{out}\over P_{in}}× 100\)

% η \(={7355\over 9000}× 100\)

% η = 81.7%