Question
Download Solution PDFA ball bearing is characterized by basic static capacity is I and dynamic capacity is 18000 N. This bearing is subjected to equivalent static load Of 5500 N. What is the life in million revolutions.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:-
Bearing loading ratio = C/P
Where,
C = Basic dynamic load rating in N
P = Equivalent static load in N
Basic rating life -
The basic rating life is based on a 90% statistical model, expressed as the total number of revolutions in 90% of the bearings in an identical group of bearings subjected to identical operating conditions will attain or surpass before flaking due to material fatigue.
For ball bearings, \(L_{10}= \left ( \frac{C}{P} \right )^3\;\).....Eqn(1)
For roller bearings, \(L_{10}= \left ( \frac{C}{P} \right )^\frac{10}{3}\;\).......Eqn(2)
Where L10 = Basic rating life 106 revolutions
Calculation:-
Given:-
A ball bearing having,, Static capacity = C1 = 11000 N, C = 18000 N, P = 5500 N
The bearing loading ratio is = C/P
⇒ C/P = 18000/5500 = 3.2727
Now, for life in millions of revolutions, we can use equation 1.
\(L_{10}= \left ( \frac{C}{P} \right )^3\;\)
\(L_{10}= \left ( \frac{18000}{5500} \right )^3= 35.053\;\)
L10 = 35.053 Million revolutions
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