A beam of the triangular section having a base width of 100 mm and height of 150 mm is subjected to a shear force of 15 kN. Find the value of the maximum shear stress.

Concept:

Table showing relations between τmax, τN.A and τavg

Calculations:

V = 15 KN

b = 100 mm

h = 150 mm

For triangular cross-section.

\(\therefore \;{{\rm{\tau }}_{max}} = \frac{3}{2}{{\rm{\tau }}_{avg}} = \frac{3}{2}\left( {\frac{V}{{\frac{{b \times h}}{2}}}} \right) = \frac{3}{2} \times \left( {\frac{{15000}}{{\frac{{100 \times 150}}{2}}}} \right) =3 \:MPa\)