A child is sitting on a swing. Its minimum and maximum heights from the ground are 0.75 m and 2 m respectively. Its maximum speed will be -

This question was previously asked in
RSMSSB Lab Assistant 2018 Official Paper
View all RSMSSB Lab Assistant Papers >
  1. 10 m/s 
  2. 5 m/s 
  3. 8 m/s  
  4. 15 m/s

Answer (Detailed Solution Below)

Option 2 : 5 m/s 
Free
RSMSSB Lab Assistant (Science) Paper I: Full Test (Latest Pattern)
3 K Users
100 Questions 200 Marks 120 Mins

Detailed Solution

Download Solution PDF

Formula Used:

Maximum Speed (v) = \(\sqrt{2g(H_2-H_1)}\)

Here, g is the acceleration due to gravity

H2 is the maximum height

H1 is the minimum height

Application:

We have,

g = 10 (assume)

H2 - H1 = 2 - 0.75 = 1.25 m

Using the above formula:

v = \(\sqrt{2\times 10 \times 1.25}= \sqrt{25}=5\ m/s\)

Latest RSMSSB Lab Assistant Updates

Last updated on May 5, 2025

-> The RSMSSB Lab Assistant Recruitment 2024 Examination Date has been released.

-> The Non-CET based examination will be conducted from 2nd to 3rd November 2025.

-> Candidates must attempt the RSMSSB Lab Assistant mock tests to check their performance.

-> The RSMSSB Lab Assistant previous year papers are also helpful in preparation.

More Damped Simple Harmonic Motion Questions

More Oscillations Questions

Get Free Access Now
Hot Links: teen patti game online teen patti all app teen patti wink