Question
Download Solution PDFA data message of 10 ms duration having 4800 bits crosses 9 nodes (10 hops) to reach its destination. The data rate and total delay for circuit switched connection (assuming node delays as 1 ms) are respectively.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
\(\rm Data rate = \frac{Total data}{Data duration}\)
Delay = No. of hops × node delay + Data duration
Calculation:
Given : Data = 4800 bits
Data duration = 10 msec
No. of hops = 10
Node delay = 1 msec.
\(\rm Data rate = \frac{4000 bits}{10 × 10^{-3}sec} = 480\space kbps\)
Delay = 10 × 1 + 10 = 20 msec
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