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A proton is about 1840 times heavier than an electron. When it is accelerated by a potential difference of 1KV, its kinetic energy will be

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  1. 920 KeV
  2. 1/1840 KeV
  3. 1 KeV
  4. 1840 KeV

Answer (Detailed Solution Below)

Option 3 : 1 KeV
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Detailed Solution

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Concept:

By conservation of energy,

The kinetic energy has to equal the change in potential energy, so

KE = q ×V

Calculation:

Given that, 

Mass of proton = 1840 × mass of electron

Potential difference (ΔV) =  1KV

By using the above concept 

(KE)final  - (KE)initial = Charge on proton × ΔV

(KE)final  -0  = (+e) × ΔV

(KE)final  = 1 KeV

∴ The required kinetic energy will be 1 KeV.

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