Question
Download Solution PDFA single-phase 111-V, 50-Hz supply is connected to a coil with 200 turns of a coil-core assembly as shown in the given figure. Find the magnitude of maximum flux in the core.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
The magnitude of net emf of an ideal transformer is given by the formula:
E = 4.44 × f × N × ϕm
Where E = RMS value of applied voltage.
f = frequency of the transformer.
N = number of turns.
ϕm = the magnitude of maximum flux in the core.
Calculation:
E = 111 V, f = 50 Hz, N = 200
111 = 4.44 × 50 × 200 × ϕm
ϕm = 111 / (4.44 × 50 × 200)
= 2.5 mWb
Last updated on May 29, 2025
-> SSC JE Electrical 2025 Notification will be released on June 30 for the post of Junior Engineer Electrical/ Electrical & Mechanical.
-> Applicants can fill out the SSC JE application form 2025 for Electrical Engineering from June 30 to July 21.
-> SSC JE EE 2025 paper 1 exam will be conducted from October 27 to 31.
-> Candidates with a degree/diploma in engineering are eligible for this post.
-> The selection process includes Paper I and Paper II online exams, followed by document verification.
-> Prepare for the exam using SSC JE EE Previous Year Papers.