A wire is bent to form a square of side 22 cm. If the wire is rebent to form a circle, then its radius will be: 

This question was previously asked in
HP JBT TET 2021 Official Paper
View all HP TET Papers >
  1. 22 cm
  2. 14 cm
  3. 11 cm
  4. 7 cm

Answer (Detailed Solution Below)

Option 2 : 14 cm
Free
HP JBT TET 2021 Official Paper
5.9 K Users
150 Questions 150 Marks 150 Mins

Detailed Solution

Download Solution PDF

Given:

The side of the square = 22 cm

Formula used:

The perimeter of the square = 4 × a    (Where a = Side of the square)

The circumference of the circle = 2 × π × r     (Where r = The radius of the circle)

Calculation:

Let us assume the radius of the circle be r

⇒ The perimeter of the square = 4 × 22 = 88 cm

⇒ The circumference of the circle = 2 × π ×  r

⇒ 88 = 2 × (22/7) × r

⇒ \(r = {{88\ \times\ 7 }\over {22\ \times \ 2}}\)

⇒ r = 14 cm

∴ The required result will be 14 cm.

Latest HP TET Updates

Last updated on Jun 6, 2025

-> HP TET examination for JBT TET and TGT Sanskrit TET has been rescheduled and will now be conducted on 12th June, 2025.

-> The HP TET Admit Card 2025 has been released on 28th May 2025

-> The  HP TET June 2025 Exam will be conducted between 1st June 2025 to 14th June 2025.

-> Graduates with a B.Ed qualification can apply for TET (TGT), while 12th-pass candidates with D.El.Ed can apply for TET (JBT).

-> To prepare for the exam solve HP TET Previous Year Papers. Also, attempt HP TET Mock Tests.

More Mensuration Questions

Get Free Access Now
Hot Links: teen patti live teen patti party teen patti master apk best teen patti 50 bonus